C Programming - Structures, Unions, Enums - Discussion

Hi Priya,
look at to the program carefully:
notice in line no. 3(where enum has declared) the order of declaration is pass=0,fail=1,then absent=2. So the order of declaration of enum is important,after that wherever we will use these variable the order will remain same it doen't matter in which order we have written it.
int main()
{
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;
stud1 = pass;
stud2 = absent;
stud3 = fail;
printf("%d %d %d\n", stud1, stud2, stud3);
return 0;
}

Hi Ranjith,

Kindly read the program very carefully.

The order of values assigned are

stud1 = pass; // here pass = 0
stud2 = absent; // here absent = 2
stud3 = fail; // here fail = 1

So,

printf("%d %d %d\n", stud1, stud2, stud3);

produces the output as 0, 2, 1.

Hope you understand. Have a nice day!

#include<stdio.h>

int main()
{
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;
stud1 = pass;
stud2 = absent;
stud3 = fail;
printf("%d %d %d\n", stud1, stud2, stud3);
return 0;
}

Actually we initialize that pass, fail, absent in the 0, 1, 2 order so the answer will be in 0, 2 1 as they asked.

Hai, If you are declare any variables in enum the default initalization is started from 0 and sequentially they are increasing. So they didn't give any initaliztion in our programm that's why bydefault initaliztion will be takes place.

So pass=0, fail=1, abscent=2.

#include<stdio.h>

int main()
{
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;

printf("%d %d %d %d \n", absent,stud1,stud2, stud3);
return 0;
}

Output: 2 51 51 8

Please explain why stud1, stud2 = 51 stud3 =8;

i = 0 1 2.

enum status {pass, fail, absent};

enum status stud1, stud2, stud3;

stud1 = pass; ->0

stud2 = absent; ->2

stud3 = fail; ->1

So 0 2 1

printf("%d %d %d\n", stud1, stud2, stud3);

Since enum members are not pre-assigned,they will be assigned with 0,1,2 by default. So as a result pass=0,fail=1,absent=2
stud1=pass=0,
stud2=absent=2,
stud3=fail=1

Hence the output:0 2 1.

@Chandan.

This is not a garbage value.

By default enum variable is an integer so, it may return 8-bit garbage value.

Please, can anybody explain Monu's program in more detail.

Hi friends look at enum status first line (pass (0), fail (1), absent (2)).

This is the reason it is displaying 0 2 1 as output, hope I am clear.

How it assigning the value 0 for pass 2 for absent and 1 for fail. Wats the logic behind this? Please tell me in detail.