C Programming - Structures, Unions, Enums - Discussion
Discussion Forum : Structures, Unions, Enums - Point Out Errors (Q.No. 7)
7.
Point out the error in the program in 16-bit platform?
#include<stdio.h>
int main()
{
struct bits
{
int i:40;
}bit;
printf("%d\n", sizeof(bit));
return 0;
}
Discussion:
19 comments Page 2 of 2.
Maheshwar Prasad said:
1 decade ago
Size is large so can't accept this "i:40" because int 32 accept 32-bit value.
Santosh said:
1 decade ago
I:30 is right and it will give output 4 in 32-bit OS.
Deepak said:
1 decade ago
If we assign like int i:30;
Is it right or wrong ?
Is it right or wrong ?
Chanders said:
1 decade ago
Yes, you are apsolutely correct.
Vikram said:
1 decade ago
It means 'i' can store an integer which contains 40 bits in it.
Generally integer size can be either 16 bits in a 16 bit machine or 32 bits in a 32 bit machine.
But here, we are trying to store 40 bits for integer which is wrong and so compiler generates error.
Generally integer size can be either 16 bits in a 16 bit machine or 32 bits in a 32 bit machine.
But here, we are trying to store 40 bits for integer which is wrong and so compiler generates error.
Ram said:
1 decade ago
int i:40;
What does it mean the above statement?
What does it mean the above statement?
Kamal said:
1 decade ago
'i:40' it means allocating the bit size for i.
Vimal said:
1 decade ago
What is meant by "i:40"?
Harshith M L said:
1 decade ago
The width of int is 4 bytes (32 bits) or 2 bytes (16 bits) depending upon the machine, so the allocation for int is upto 32 bits. The declaration int i:40; exceeds the width of int so the compiler generates the error:width of 'i' exceeds its type.
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