C Programming - Strings - Discussion
Discussion Forum : Strings - Find Output of Program (Q.No. 11)
11.
What will be the output of the program ?
#include<stdio.h>
#include<string.h>
int main()
{
static char str1[] = "dills";
static char str2[20];
static char str3[] = "Daffo";
int i;
i = strcmp(strcat(str3, strcpy(str2, str1)), "Daffodills");
printf("%d\n", i);
return 0;
}
Discussion:
31 comments Page 2 of 4.
Prakrati said:
1 decade ago
You all please run this code. It will give some negative result cause static char str3[] = "Daffo";memory is fixed. So this concatination is not possible. Target string should have enough memory.
Mounika.p said:
1 decade ago
i = strcmp(strcat(str3, strcpy(str2, str1)), "Daffodills");
first it will copy str1 to str2.and then by string concatinating str3 with str2..it will give Daffodills.after that string comparision between to strings.these two strings are same.so strcmp of this two strings gives 0 value...that's enough about this programme...
first it will copy str1 to str2.and then by string concatinating str3 with str2..it will give Daffodills.after that string comparision between to strings.these two strings are same.so strcmp of this two strings gives 0 value...that's enough about this programme...
Kritika said:
1 decade ago
strings are immutable and of reference type, that's y this copy in str3 is allowed.
Mano said:
1 decade ago
i=strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");
//str1=dills
//str2=char[20]
//str3=daffo
1. strrcpy(str2,str1):
str2=dills //str1 value is copied to str2
2. strcat(str3,str2):
daffodills//str3+str2
3. strcmp(daffodills,daffodills)
They are equal hence 0 is correct.
//str1=dills
//str2=char[20]
//str3=daffo
1. strrcpy(str2,str1):
str2=dills //str1 value is copied to str2
2. strcat(str3,str2):
daffodills//str3+str2
3. strcmp(daffodills,daffodills)
They are equal hence 0 is correct.
Raju Singh Kumai said:
1 decade ago
i=strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");
The statement will be solved in this order :
1-> strcpy(str2,str1))
This will cause the value of str1 "dills" to be copied in str2.
2->strcat(str3,strcpy(str2,str1)))
The value of strcpy(str2,str1) will be -> "dills"
So the result of iot will be "daffodills"
3->strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");
Or in short[strcmp("daffodills","daffodills")]
In strcmp if both are same then 0 is return otherwise -1 or 1 is return depending on Left or right Exp is Greater.
So 0 will be return.
The statement will be solved in this order :
1-> strcpy(str2,str1))
This will cause the value of str1 "dills" to be copied in str2.
2->strcat(str3,strcpy(str2,str1)))
The value of strcpy(str2,str1) will be -> "dills"
So the result of iot will be "daffodills"
3->strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");
Or in short[strcmp("daffodills","daffodills")]
In strcmp if both are same then 0 is return otherwise -1 or 1 is return depending on Left or right Exp is Greater.
So 0 will be return.
Sus said:
1 decade ago
First it will copy str1 value to str2, then it will concatenate, and then compare.
Harsh said:
1 decade ago
As strings are immutable how is the strings modified.
Shabana said:
1 decade ago
Condition is that string cmp.
1- Strcpy. the str1 is copy to str2 it will print dills.
2- The str2 and str3 multiply done and it will DOffodills it will matches the Daffo. Both ASCII values are same so it will 0.
1- Strcpy. the str1 is copy to str2 it will print dills.
2- The str2 and str3 multiply done and it will DOffodills it will matches the Daffo. Both ASCII values are same so it will 0.
Anusha.v said:
1 decade ago
I agree with @Goutham's answer, but yet I didn't understood what is the role of static char in this programme?
Konstantinos said:
1 decade ago
static char str3[] = "Daffo";
//6 chars length (5+1) memory reserved!
strcat (str3, strcpy (str2, str1));
//copy in to a 6 chars reserved memory 11 chars (10+1) !
As you can see from the below.
char *strcat (char *dest, const char *src).
Dest -- This is pointer to the destination array, which should contain a C string, and should be large enough to contain the concatenated resulting string.
From what you see the above should produce a memory corruption!
//6 chars length (5+1) memory reserved!
strcat (str3, strcpy (str2, str1));
//copy in to a 6 chars reserved memory 11 chars (10+1) !
As you can see from the below.
char *strcat (char *dest, const char *src).
Dest -- This is pointer to the destination array, which should contain a C string, and should be large enough to contain the concatenated resulting string.
From what you see the above should produce a memory corruption!
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