C Programming - Strings - Discussion

i=strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");


The statement will be solved in this order :

1-> strcpy(str2,str1))

This will cause the value of str1 "dills" to be copied in str2.

2->strcat(str3,strcpy(str2,str1)))

The value of strcpy(str2,str1) will be -> "dills"

So the result of iot will be "daffodills"

3->strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");
Or in short[strcmp("daffodills","daffodills")]

In strcmp if both are same then 0 is return otherwise -1 or 1 is return depending on Left or right Exp is Greater.

So 0 will be return.

static char str3[] = "Daffo";
//6 chars length (5+1) memory reserved!

strcat (str3, strcpy (str2, str1));
//copy in to a 6 chars reserved memory 11 chars (10+1) !

As you can see from the below.

char *strcat (char *dest, const char *src).

Dest -- This is pointer to the destination array, which should contain a C string, and should be large enough to contain the concatenated resulting string.

From what you see the above should produce a memory corruption!

Here str1 [] = "dills".
str2[20]
str3[] = "Daffo"
int i

The condition is checked by the form precedence and associativity
i = strcmp(strcat(str3, strcpy(str2, str1)), "Daffodills")
printf("%d\n", i)

i = strcmp(strcat(str3, "dills"), "Daffodills")
i = strcmp("Daffodills", "Daffodills")
i = 0
Then, by the stcmp conditions,
if Str 1 == str2 -> 0.
str1 > str2 -> +ve value.
str1 < str2 -> -ve value.

It is simple.

strcpy(str2,str1) : here "dills" will be copied to str2.
Hence str2 contains " dills"

strcat(str3,str2) : "dills" will be concatenated with "daffo"
Hence str3 contains " Daffodills ".

At last strcmp compares with the string str3 with "Daffodills" and pass the value "0" since the string matches.

i = strcmp(strcat(str3, strcpy(str2, str1)), "Daffodills");
first it will copy str1 to str2.and then by string concatinating str3 with str2..it will give Daffodills.after that string comparision between to strings.these two strings are same.so strcmp of this two strings gives 0 value...that's enough about this programme...

i=strcmp(strcat(str3,strcpy(str2,str1)),"daffodills");

//str1=dills
//str2=char[20]
//str3=daffo

1. strrcpy(str2,str1):

str2=dills //str1 value is copied to str2

2. strcat(str3,str2):

daffodills//str3+str2

3. strcmp(daffodills,daffodills)

They are equal hence 0 is correct.

step 1: strcpy(str2,str1) cpoy the str1="dills" into str2.

step 2: strcat(str3,str2) append the dills at the end of Daffo.

step 3: strcmp(str3,"Daffodils") returns the no. of charecters of str3 which are not find in Daffodills.

step 4: since both strings are same so results will be 0(zero)

Condition is that string cmp.

1- Strcpy. the str1 is copy to str2 it will print dills.
2- The str2 and str3 multiply done and it will DOffodills it will matches the Daffo. Both ASCII values are same so it will 0.

Str1=dills
Strcpy(str2,str1) it gives str2 = dills
Strcat(str3,str2) gives str3 = daffodills
Strcmp(str3,"daffodils")=it gives 0 ,in string comparison if condition is true it will return 0 else 1.

Str1=dills.
Strcpy(str2,str1) it gives str2 = dills.
Strcat(str3,str2) gives str3 = daffodills
Strcmp(str3,"daffodils")=it gives 0 ,in string comparison if condition is true it will return 0 else 1.