C Programming - Strings - Discussion
Discussion Forum : Strings - Find Output of Program (Q.No. 28)
28.
If the size of pointer is 4 bytes then What will be the output of the program ?
#include<stdio.h>
int main()
{
char *str[] = {"Frogs", "Do", "Not", "Die", "They", "Croak!"};
printf("%d, %d", sizeof(str), strlen(str[0]));
return 0;
}
Answer: Option
Explanation:
Step 1: char *str[] = {"Frogs", "Do", "Not", "Die", "They", "Croak!"}; The variable str is declared as an pointer to the array of 6 strings.
Step 2: printf("%d, %d", sizeof(str), strlen(str[0]));
sizeof(str) denotes 6 * 4 bytes = 24 bytes. Hence it prints '24'
strlen(str[0])); becomes strlen(Frogs)). Hence it prints '5';
Hence the output of the program is 24, 5
Hint: If you run the above code in 16 bit platform (Turbo C under DOS) the output will be 12, 5. Because the pointer occupies only 2 bytes. If you run the above code in Linux (32 bit platform), the output will be 24, 5 (because the size of pointer is 4 bytes).
Discussion:
10 comments Page 1 of 1.
Anubhav singh said:
1 decade ago
*str[] is declared as the array of pointer not the pointer to an array.
Then, str points to the base address of the declaration i.e., to the "frogs",
Size of frogs is 6*4 (because the format specifier is of int),
Similarly strlen (str[0]) => strlen ("frogs") which will give 5.
Note that, sizeof counts the '\0' character at the end of string for calculation whereas strlen does not.
Then, str points to the base address of the declaration i.e., to the "frogs",
Size of frogs is 6*4 (because the format specifier is of int),
Similarly strlen (str[0]) => strlen ("frogs") which will give 5.
Note that, sizeof counts the '\0' character at the end of string for calculation whereas strlen does not.
Balaji said:
5 years ago
Initially we know that the size of the operator will give one extra value because
it is a[] = "hello";
sizeof(a) -> 5+1 -> 6;
because it is a single string.
And here it is an array of the pointer so it gives the array size.
it is a[] = "hello";
sizeof(a) -> 5+1 -> 6;
because it is a single string.
And here it is an array of the pointer so it gives the array size.
Deepak Chauhan said:
10 years ago
Here pointer array consist of 6 strings and size of pointer is 4 byte in 32 bit system and 8 byte in 64 bit system.
Hence 6 strings* 4 byte each = 24 byte is sizeof str.
While string length of "frogs" is 5 since it consist of 5 character.
Hence 6 strings* 4 byte each = 24 byte is sizeof str.
While string length of "frogs" is 5 since it consist of 5 character.
Utkarsh said:
6 years ago
@All.
Here is what I found:
Linux GCC on Ubuntu 18.04 gives output:
48 and 5.
Turbo C/C++ 3.2 gives output:
10 and 5.
Which is correct one, Please anyone tell me.
Here is what I found:
Linux GCC on Ubuntu 18.04 gives output:
48 and 5.
Turbo C/C++ 3.2 gives output:
10 and 5.
Which is correct one, Please anyone tell me.
Amogh Gowda said:
8 years ago
@Anubhav Singh.
You said sizeof will count \0 also then in str there are 6 strings=6*4=24.
And one null character so it should be 24+1=25.
You said sizeof will count \0 also then in str there are 6 strings=6*4=24.
And one null character so it should be 24+1=25.
Bunny said:
7 years ago
Previously we counted a null character in "sizeof () " function but in this question we didn't why? Please explain.
Anonymous said:
10 years ago
How come strlen (str[0]) will work? Without using #include<string.h>.
(1)
Susanta said:
1 decade ago
So what is the declaration of array of pointer?
Ankur chaurasiya said:
1 decade ago
Can you explain it in detail?
Renuvicky said:
9 years ago
Can you explain it in detail?
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