C Programming - Strings - Discussion

Discussion Forum : Strings - Find Output of Program (Q.No. 8)
8.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    char str[7] = "IndiaBIX";
    printf("%s\n", str);
    return 0;
}
Error
IndiaBIX
Cannot predict
None of above
Answer: Option
Explanation:
Here str[] has declared as 7 character array and into a 8 character is stored. This will result in overwriting of the byte beyond 7 byte reserved for '\0'.
Discussion:
12 comments Page 1 of 2.

Amit kumar said:   3 years ago
This programs gives the output as IndiaBI.

So, the correct option is D.

Naman_Shah said:   9 years ago
According to me,

Output is IndiaBi, because the array initialize up to 7 characters. So the Answer should be option 'D' because IndiaBi is not mentioned.

Thank you!!!

Deepak Chauhan said:   10 years ago
Since the answer depends on compiler hence cannot predict option C.

Ajamathusen Jahagirdar said:   10 years ago
Answer for these question will be none of above because output of the program is IndiaBI and it is constant and no other option matches the output so answer will be none of above.

Anusha.v said:   1 decade ago
Answer can be Indiabi since when we compile this progamme it is giving Indiabi as answer someone is saying it depends on the compiler. Based on that condition we can say that answer is not predictable.

Kanak vashistha said:   1 decade ago
Why shouldn't be the answer of this question is an error can anyone explain me?

Taj said:   1 decade ago
In the gcc compiler output observed "IndiaBi" with following warning:

Warning : Initializer-string for array of chars is too long [enabled by default].

char str[7] = "IndiaBIX";

Radhika said:   1 decade ago
Online C compiler also gives the answer like option D.

Amrit said:   1 decade ago
Looks like that the answers depends on the compiler used, so option C would be the ans, since one can't predict the answer.

Arya said:   1 decade ago
A compile time error comes in Turbo C-"Too many initialisers".


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