C Programming - Strings - Discussion
Discussion Forum : Strings - Find Output of Program (Q.No. 22)
22.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char str = "IndiaBIX";
printf("%s\n", str);
return 0;
}
Answer: Option
Explanation:
The line char str = "IndiaBIX"; generates "Non portable pointer conversion" error.
To eliminate the error, we have to change the above line to
char *str = "IndiaBIX"; (or) char str[] = "IndiaBIX";
Then it prints "IndiaBIX".
Discussion:
5 comments Page 1 of 1.
Allauddin Pirjade said:
7 years ago
Char data types takes only one or two characters that's why it giving error.
If we use char* or char[ ] then it prints whole string.
If we use char* or char[ ] then it prints whole string.
Syed Ahmed said:
8 years ago
@Rishi.
It should have worked. Show your code, we can debug it.
It should have worked. Show your code, we can debug it.
Rishi said:
9 years ago
I tried it both ways i.e by using *str, str[ ] it's not working.
Someone help me to get this.
Someone help me to get this.
Yuganya said:
1 decade ago
What is meant by "Non portable pointer conversion" error?
Sudheer said:
1 decade ago
What do we mean by segmentation fault?
And why dev c++ prints NULL for this problem.
And why dev c++ prints NULL for this problem.
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