C Programming - Strings - Discussion

When you will assign any value to a pointer variable then compiler will automatically convert given value in address of pointer type such automatic type conversion is known as non-portable pointer conversion. Non-portable pointer conversion is not cause of any compilation error but it is bad coding style. Hence compiler will send one warning message.

For example:

#include<stdio.h>
void main(){
int a =10;
int *p;
int **q;
p=a; //Nonportable pointer conversion
q=a; //Nonportable pointer conversion
printf("%d %d",*p,**q);
}

When you will assign any value to a pointer variable then compiler will automatically convert given value in address of pointer type such automatic type conversion is known as non-portable pointer conversion. Non-portable pointer conversion is not cause of any compilation error but it is bad coding style. Hence compiler will send one warning message.

Hello,

The code in Linux works find and gives "India" as the answer. The reason is this: in the declaration :

char str[10]="India";

// the stringlength is 5 so the
// the string terminator will be at str[5]
// any operation after str[5] will be not
// valid.

str[10]="india"
sttr[6]="bix"
printf"%s",str);

Here what will be output?

Can we initialize same string variable str, twice with different size?

Hello all,

Here data type for str[6]="BIX"; is not defined so it will not consider as a string.
It should be de char str[6]="BIX"; then it will print BIX.

I got the warning.

"Assignment makes integer from pointer without a cast". But there is a smooth compilation of the code with the output as "India".

I thought that overwriting in strings is not possible by accessing directly.

When i execute this in gcc compiler it gives the o/p as India.

Can any one explain non-portable conversion ?

So what will be the output? How is it error?