C Programming - Pointers - Discussion

* is a correct answer. I agree with the given option.

* is known as a de-referencing operator which de-reference the address stored in the pointer. That is fetched the value from that address which pointer is pointing to.

&&, || operator which operation performed?

I think & is used for address.

#include<stdio.h>
#include<conio.h>
void main()
{
int a=10;
int *p;
p=&a;
printf("value of A %d",a); //Output-10.
printf("value of A %d",*P); //Output-10.
printf("Address of A %p",a); //Output-fff2.
printf("value of p %d",p); //Output-fff2.
printf("Address of p %d",p); //Output-fff4.

If we want to fetch the address of a variable we use & and on the other hand if we want to fetch the value from the address we use *.

Hello,

I have executing this code and thus it is perfect.

#include <stdio.h>

void main() {
// your code goes here

int x=10;

int *y;
y=&x;
printf("value at Y is %d\n",y);
printf("value at *Y is %d\n",*y);
printf("value at &Y is %d\n",&y);
}

Value at Y is -1076357592.
Value at *Y is 10.
Value at &Y is -1076357588.
--------------------------------------------------------------

So to conclude:

y gives address of x.
*y gives data of x.
&y gives the address of y. The memory which contains the address of x.

Basically pointer variable is called & operator.

Pointer is used to store the address of the variable of same type. Ex. char *ptr can be used to store address of char ch..

We use & operator to assign the address of variable to pointer Ex. ptr=&ch;

And we use * operator to get value stored at particular address stored in pointer var. Ex. char chh=*ptr;

Hi, & defines address in memory, * represents the value of pointer.