C Programming - Pointers - Discussion
Discussion Forum : Pointers - General Questions (Q.No. 5)
5.
If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable?
Discussion:
60 comments Page 1 of 6.
Deepak said:
5 years ago
@All.
The eg Syntax is;
struct node
{
int data;
};
main(){
struct node p,*a;
P.data=10;
a=&p;
printf(" %d",a->data);
}
And Output is 10.
The eg Syntax is;
struct node
{
int data;
};
main(){
struct node p,*a;
P.data=10;
a=&p;
printf(" %d",a->data);
}
And Output is 10.
(5)
Ashish said:
9 years ago
I think the answer given to the question is wrong.
We can use(*p).x instead of using ->.
We can use(*p).x instead of using ->.
(3)
Priya said:
9 years ago
I did not understand this question. Please help me to get this.
(3)
Swapnika said:
6 years ago
Dot (.) operator also used in pointers.
(3)
Apurva Nigam said:
1 decade ago
@Raghushri:
We can access the elements of structures using "." also.
Eg:- obj.element
@ everybody:
Do we necessarily need to use "->" for a variable which is a pointer to a structure to access data members of the structure????
We can access the elements of structures using "." also.
Eg:- obj.element
@ everybody:
Do we necessarily need to use "->" for a variable which is a pointer to a structure to access data members of the structure????
(2)
Maahi said:
1 decade ago
So finally which operator should be used? can any one tell?
(2)
Kisan said:
1 decade ago
. : used to access structure members with normal structure
variable.
-> : used to access structure members with pointer to structure
* : used to dereference a pointer.
& : used to obtain address of variable.
variable.
-> : used to access structure members with pointer to structure
* : used to dereference a pointer.
& : used to obtain address of variable.
(2)
Manmeet said:
1 decade ago
When ever we want to fetch the value out of a pointer variable which is store in a structure.
We always use -> (arrow) pointer.
On the other hand if in a structure we have a simple variable of any data type we will use .(dot) operator to fetch the value from a variable.
We always use -> (arrow) pointer.
On the other hand if in a structure we have a simple variable of any data type we will use .(dot) operator to fetch the value from a variable.
(1)
Sufiyan said:
1 decade ago
Very good logic. Can you elaborate it?
(1)
Jatin said:
1 decade ago
Here we can use arrow operator to access structure members without creating structure variable that's why we used -> (arrow) operator.
(1)
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