C Programming - Pointers - Discussion

float****: This part specifies the return type of the function, which is a pointer to a pointer to a pointer to a pointer to a float. This is what you want to return from the function.

Fun: This is the name of the function.

(float***): This part specifies the parameter of the function, which is a pointer to a pointer to a pointer to a float. This matches the requirement of receiving a pointer to a pointer to a pointer to a float.

So, the correct declaration float ****fun(float***); ensures that the function takes the correct type of argument and returns the desired type of result as specified in your question.

From the given question,

"... receives a pointer to pointer to a pointer to a float... " = ***

"... returns a pointer to a pointer to a pointer to a pointer..." = ****

Therefore, float ****fun (float ***) is the correct answer.

If you want to receive a pointer then you can us a symbol " * ";

and if you want to return a pointer then you can us a symbol " * ";.

So as per our question that is "receives a "pointer to pointer to a pointer to a float".

We can use "float***"and same for function.

Can anybody explain This concept again? is it necessary if you passing (int***) to function the function return type should be 'void/int/float ***fun()';

There are four pointers points to function fun and the argument it receives have three pointers.

float ****fun(float***);
is this possible i mean return value can also be in pointing thing????

float ****fun(float***);
Is this possible i mean return value can also be in pointing thing ?

@Sundar.

Your explanation is very clear. I got it now. Thank you very much.

Simple trick to learn:

No. of Pointer (words) use in Q = no. of '*' take.

I can't understand this, please anyone explain it properly.