C Programming - Pointers - Discussion

Here str1 points to I of India first. str2 points B of BIX... in while loop B of bix is assigned to I of india now string value changes to Bndia since assignment statement is executed successfully Bndia is printed. now str1 points to n of Bndia and str2 points to I of BIX again n is replaced by I ... this condition is continued till '\0' is encountered where assignment statement fails and the program comes out of the loop.

#include<stdio.h>

int main()
{

char aa[]="1stString";
char bb[]="2nd";
char *sa,*sb;
sa=&aa;sb=&bb;

while (*sa=*sb)
{
printf("Value for while condition: %c,\n",*sa=*sb);
*sa++;
*sb++;
}
}

Try this, and you will see, that "=" operator gives back other values, than true.

Thanks raju.

It was good explanation.

1st step:

I is replaced by B. So str1=Bndia.

Now on op: Bndia

2nd step:

s1 points to 'i' of str1 and s2 points to 'I'of str2.
so str1 becomes BIdia.
now on op: BndiaBIdia

3rd step:
output is appended by BIXia.
so now op: BndiaBIdiaBIXia.

4th step:
s2 points to '\0' i.e null character.
so s1 becomes null.
so in the while loop condition,

while('\0')=while(false).

So compiler comes out of loop.

Actually in this program it working like this.

Case 1: Post increment is happening.

Case 2: STR1's character replacing with str2's fist character then printing Bndia then incrementing one so second will BIdia then once again increment so it will print BIXia.

Thanks raju.

Thanks raju and anand, subbu.

str1="india" str2="bix"
so
first->bndia
second->bidia
third->bixia

Thanks raju.

What raju said on 17th sep was right.

Beyond that I want to tell something is that, while loop is longlasting upto string sizes of both strings are matched i.e => bix=ind.

Now upto this condition there will be 2 increments of both s1, s2.

As at 2nd itteration BI{size)is still less than Ind(size), it will not violate while loop & print BIdia same as raju already told.

Next itteration is last one b'z BIX (srng size) matches with dia(size)& now s2 get assigned to s1 i.e =>BIXia lastly get print.