C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 20)
20.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char str1[] = "India";
char str2[] = "BIX";
char *s1 = str1, *s2=str2;
while(*s1++ = *s2++)
printf("%s", str1);
printf("\n");
return 0;
}
Discussion:
43 comments Page 1 of 5.
Fatma mofreh said:
2 years ago
First step:
*s1++ point to I and *s2++ point to B
the first while loop I is replaced by B
so the first output will be Bndia
Second step:
*s1++ point to n and *s2++ point to I
The second while loop n is replaced by I
So the second output will be BIdia.
Third step:
*s1++ point to d and *s2++ point to X
The third while loop d is replaced by X.
So the third output will be BIXia.
Then;
*s2++ point to null so while is ended.
then print \n
*s1++ point to I and *s2++ point to B
the first while loop I is replaced by B
so the first output will be Bndia
Second step:
*s1++ point to n and *s2++ point to I
The second while loop n is replaced by I
So the second output will be BIdia.
Third step:
*s1++ point to d and *s2++ point to X
The third while loop d is replaced by X.
So the third output will be BIXia.
Then;
*s2++ point to null so while is ended.
then print \n
(7)
Riswan said:
6 years ago
Thanks to you all.
Raja said:
7 years ago
Thanks @Avi.
Manish said:
7 years ago
I think while need a condition but there is '='assignment operator that can only assign the value so. It couldn't run.
Rohan said:
7 years ago
You are absolutely right @Sowmya.
str1 value must be "India" as output.
str1 value must be "India" as output.
Sowmya said:
8 years ago
Hello friends,
str1 values r stored in S1 , we r operating on S1, str1 values remain same kW,in pf statement we should print the values of str1, so str1 values should be "India " kw.
str1 values r stored in S1 , we r operating on S1, str1 values remain same kW,in pf statement we should print the values of str1, so str1 values should be "India " kw.
(1)
SHIVANI said:
8 years ago
Thank you all.
(1)
Suraj said:
8 years ago
The 1st letter of *s2++ is BIX = 'B'.
'B' is assigned to the 1st letter of S1 so it becomes Bndia.
After that *S2++ mens increment by +1 so the result is BI now replace with *S1++ first two letters are BIdia(dia) from S1 we assign S2 in S1 .after that increment *S2++ so the result is BIX and it replaced 3 letter with S1 and then print.
Hope you understand.
'B' is assigned to the 1st letter of S1 so it becomes Bndia.
After that *S2++ mens increment by +1 so the result is BI now replace with *S1++ first two letters are BIdia(dia) from S1 we assign S2 in S1 .after that increment *S2++ so the result is BIX and it replaced 3 letter with S1 and then print.
Hope you understand.
(2)
Emanuel said:
9 years ago
I think it will be BIX.
(1)
Praju said:
9 years ago
Well done @Uttam.
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