C Programming - Pointers - Discussion

#include<stdio.h>

int main()
{
char str[] = "peace";
char *s = str;
printf("%s\n", s++ +3);
printf("%s\n", s+3);
return 0;
}

Run this. You will know diff.

*s = base address of str.
Now s is pointing to p.

Since s++ is a post increment, it gets incremented 3 times, not before that. So s is pointing to c.

So it points from "ce".

Printf ("%c\n", s++ +3);// This will print only c right?

int main()
{
char str[] = "peace";
char *s = str;
printf("%s\n", ++s +2);
return 0;
}

It will print as "ce". Because pre-increment and post-increment concept is also included in this code.

=> s++, executes later after printing the string for the first time.

Rest what remains is s+3, which makes the pointer point to c and from there it will print the remaining string.

Thanks @Monika.

Thanks @Monika.

++ is the unary operator and + is a binary operator.
unary given higher precedence over binary.
so ++ should consider.

Is it right?

@All.

Please consider this.

#include<stdio.h>

int main()
{
char str[]="peace";
char *s = str;
printf("%s\n",++s +3);
return 0;
}

@ALL.

#include<stdio.h>
int main()
{
Step1: char str[] = "peace";
/* It will declare str[] array as character and store peace in it.*/

Step 2: char *s = str;
/* It will declare a pointer variable (s) as character and store the content of str. */

Step3: printf("%s\n", s++ +3);
/* It will print the string (as specified %s) , the next question is what?

(i) s++ --> It will point to "p" because it is post_increment operator and still contain string as "peace".
(ii) s++ +3 = add three positions (i.e. At present , it is pointing to s[0] but after incrementing s[0+3] =s[3] , and it is pointing to "c" position no. 3) and prints further (i.e. "ce").
return 0;
}