C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 16)
16.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char str[] = "peace";
char *s = str;
printf("%s\n", s++ +3);
return 0;
}
Discussion:
40 comments Page 4 of 4.
Lavanya said:
2 decades ago
I need answer description for this.
Suresh said:
1 decade ago
Here *s is a string pointer...s++ means it increases n times..but the pointer comes to the same position..i.e"peace"..now +3 means it gets incremented 3 times..i.e it starts from after 3 chaectrs in string..i.e "c"..so it prints "ce"..
Ranu said:
1 decade ago
All this kind of expression which include + are calculated from right to left of ().
Rohit said:
1 decade ago
Hi.
Here s++ will be executed after the printf statement execution so there will be no effect of increment operator in this printf statement and it will print 'ce' due to +3.
Here s++ will be executed after the printf statement execution so there will be no effect of increment operator in this printf statement and it will print 'ce' due to +3.
Kiran said:
1 decade ago
Here s++ +3;
The + is more priority than ++ operator.
Then s is incremented to 3 bytes. Then it will print.
You all guys have one doubt that is what about ++ ?
In printf statement only one expression type executed accorrding to its priority based.
That's why here s+3 only occur.
The + is more priority than ++ operator.
Then s is incremented to 3 bytes. Then it will print.
You all guys have one doubt that is what about ++ ?
In printf statement only one expression type executed accorrding to its priority based.
That's why here s+3 only occur.
Piyush said:
1 decade ago
Thanks monika.
Sukrutha said:
1 decade ago
Thanks monika.
Poonam said:
1 decade ago
Thanks monika.
Roshan said:
1 decade ago
Thanks monika...
Akshay said:
1 decade ago
Whats the output if they ask like below.......
printf("%d\n", ++s +3); instead of;;
printf("%d\n", s++ +3);
printf("%d\n", ++s +3); instead of;;
printf("%d\n", s++ +3);
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