C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 14)
14.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char *str;
str = "%d\n";
str++;
str++;
printf(str-2, 300);
return 0;
}
Discussion:
43 comments Page 4 of 5.
Vallabh said:
1 decade ago
Because it will take it as :
printf("%d",300); and print 300.
But in case like
char *str;
str="abc";
printf(str,"mno\n");
The output will be "abc".
printf("%d",300); and print 300.
But in case like
char *str;
str="abc";
printf(str,"mno\n");
The output will be "abc".
Vinay said:
1 decade ago
We all know that we cannot substract any integer value in pointer then how can we substract 2 in it please. Any one who know answer this ?
Mitali said:
1 decade ago
But here the value of str is not replaced by the value enclosed in double quote. So how is this possible?
Vijay said:
2 decades ago
Hi guys,
Can anyone give the explanation for this problem?
Can anyone give the explanation for this problem?
Srbh said:
1 decade ago
char *ch;
ch="%d";
printf(ch,300);
printf("ch\n",300);
printf(ch,"300");
Anyone please explain me how these 3 printf statements differs ?
ch="%d";
printf(ch,300);
printf("ch\n",300);
printf(ch,"300");
Anyone please explain me how these 3 printf statements differs ?
Alok Kumar said:
1 decade ago
char *ch;
ch="%s\n";
ch++;
ch++;
printf(ch-2,300);
Please explain it.
ch="%s\n";
ch++;
ch++;
printf(ch-2,300);
Please explain it.
PAVIforlove said:
1 decade ago
Assume ch address is 100.
The ch pointer variable store the %d.
In memory location 100.
After increment it would be 101 then 102.
While printing ch-2 means 102-2 then it again pointing 100th location in 100 location it contains "%d" then it will print 300.
The ch pointer variable store the %d.
In memory location 100.
After increment it would be 101 then 102.
While printing ch-2 means 102-2 then it again pointing 100th location in 100 location it contains "%d" then it will print 300.
Srk said:
1 decade ago
Consider str is pointing to 1002.
If we increment it by one 1002+sizeof(char)*1 (size of chat is 2 bytes so it will Point to next location (1004) that is explicitly casted to store char,
( str = (char *)(str+1*sizeof(char)) )
To 1004 contains a garbage value and similarly 1006.
but in printf statement we will make the pointer to point 1002.
If we increment it by one 1002+sizeof(char)*1 (size of chat is 2 bytes so it will Point to next location (1004) that is explicitly casted to store char,
( str = (char *)(str+1*sizeof(char)) )
To 1004 contains a garbage value and similarly 1006.
but in printf statement we will make the pointer to point 1002.
Santhisuresh said:
1 decade ago
We gave str++ two times it gives str=str+2. In printing we are subtract 2 from str+2(i.e str+2-2). Therefore it prints the same value.
Sahana said:
1 decade ago
printf("%d",300); and print 300.
But in case like:
char *str;
str="abc";
printf(str,"mno\n");
The output will be "abc".
But in case like:
char *str;
str="abc";
printf(str,"mno\n");
The output will be "abc".
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