C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 14)
14.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    char *str;
    str = "%d\n";
    str++;
    str++;
    printf(str-2, 300);
    return 0;
}
No output
30
3
300
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
43 comments Page 1 of 5.

Vijay said:   2 decades ago
Hi guys,

Can anyone give the explanation for this problem?

Archana said:   2 decades ago
Twice str is incremented n then when we do str-2, it is again pointing to starting position. So str contains "%d\n".

So printf statement would be like printf("%d\n",300);

Hence output will be 300.

Sunitha said:   1 decade ago
Thank you very much archana.

Sohan lal mits said:   1 decade ago
We know that when we increament pointer wihh n values like then pointer point to nth value address and whereas pointer decrease with nth value so pointer locate same address as previus so according question
char *str;
str = "%d\n";
str++;
str++;
printf(str-2, 300);
output:300

Suresh said:   1 decade ago
Thank you sohan lal mits. There is clearance in your explanation. Thanks a lot.

Pavan said:   1 decade ago
Thank you sohan and archana.

Sujith said:   1 decade ago
str-2 one's incremented then it becomes str-1
then again incremented then it becomes str
then str="%d\n"; then 300 will print

Jasmin said:   1 decade ago
Can any body explain what happened to printf (str-2, 300) why only 300 is answer ? Why the value of str-2 is not printed. ?

Vallabh said:   1 decade ago
Because it will take it as :

printf("%d",300); and print 300.

But in case like

char *str;
str="abc";
printf(str,"mno\n");

The output will be "abc".

Vinay said:   1 decade ago
We all know that we cannot substract any integer value in pointer then how can we substract 2 in it please. Any one who know answer this ?


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