C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 5)
5.
What will be the output of the program If the integer is 4bytes long?
#include<stdio.h>
int main()
{
int ***r, **q, *p, i=8;
p = &i;
q = &p;
r = &q;
printf("%d, %d, %d\n", *p, **q, ***r);
return 0;
}
Discussion:
35 comments Page 2 of 4.
Perumalsamy said:
1 decade ago
First assume i=8
and then
p =&i; // p holds address of i
q=&p; // q holds address of p
r=&q; // and r holds address of q
*p means value of i;
**q and ***r and is called chain pointer that means
p<-q<-r
So all value is 8.
and then
p =&i; // p holds address of i
q=&p; // q holds address of p
r=&q; // and r holds address of q
*p means value of i;
**q and ***r and is called chain pointer that means
p<-q<-r
So all value is 8.
Uttam said:
1 decade ago
Let the addresses of variables i,p,q,r are 0x100,0x200,0x300,0x400 respectively.
Here p,q,r are pointers.
p holds address of i.ie 0x100.
q holds address of p.ie 0x200.
r holds address of q.ie 0x300.
so we can say r is the pointer which indirectly refers to the address of variable i.
so value that pointer r holds is indirectly equal to the value of i.
Here p,q,r are pointers.
p holds address of i.ie 0x100.
q holds address of p.ie 0x200.
r holds address of q.ie 0x300.
so we can say r is the pointer which indirectly refers to the address of variable i.
so value that pointer r holds is indirectly equal to the value of i.
Madhu said:
1 decade ago
If it declaired that int i,*p then
p= &i (it means p stores the address of i)
*p=value at i
same way
q= &p
**q=value at &i(it means pointer to a integer pointer)
***r= value at &i(it means pointer to a pointer to a poiter )
and it has no limit to extend this pointer to pointer so we can use number of' *'.but all are print only the value so it prints 8,8,8.
p= &i (it means p stores the address of i)
*p=value at i
same way
q= &p
**q=value at &i(it means pointer to a integer pointer)
***r= value at &i(it means pointer to a pointer to a poiter )
and it has no limit to extend this pointer to pointer so we can use number of' *'.but all are print only the value so it prints 8,8,8.
Zohra said:
1 decade ago
Well explained. Sunil.
Tarun said:
1 decade ago
@Jyothi. Explain nicely thanks for understand me.
Shashank sinha said:
1 decade ago
Thanx Jyoti
Ramya said:
1 decade ago
Here r contains ***r so it point the i pointer variable.
And q contain the ** pointer variable. And p contain the * pointer variable so it point the i pointer address value.
And q contain the ** pointer variable. And p contain the * pointer variable so it point the i pointer address value.
Sumallika said:
1 decade ago
p=&i
*p=*(&i)=i
so *p=8;
q=&p,
*q=*(&p)=p,
**q=*p,
**q=8;
r=&q,
*r=*(&q)=q
**r=*q,
***r=**q,
***r=8
*p=*(&i)=i
so *p=8;
q=&p,
*q=*(&p)=p,
**q=*p,
**q=8;
r=&q,
*r=*(&q)=q
**r=*q,
***r=**q,
***r=8
Manjiri shastri said:
10 years ago
Can you please tell me how it work? I mean how pointer storing the address?
Harendra gotla said:
9 years ago
Thank you @Sumallika, the way you solve the problem is clever and easy to understand.
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