C Programming - Pointers - Discussion

Guys one important of pointers is

* stands for value at address
& address of

Since p is a pointer variable which stores only the address it contains address of h (i.e base address of let us say 500)

printf("%s\n",*&*&p);

*&*&p - value at address( address ( value at address ( address ( p))))
-> value at address( address ( value at address ( 500)))
-> value at address( address ( h))
-> value at address(500)
-> h

Since %s represents a string it prints starting from h which is hello.
hope this helps!

Hello, can anyone explain me this?

Char *p.

Here *p is a pointer so it can store the only address of a character. But we are assigning it a string? How is that possible?

@Deepu is right and people who saying p="hello" are wrong because p is a pointer so *p=h; since it is string it will print hello.

Referencing and address operator are canceling each other.

Here is the direct assignment to the pointer. So hello is printed.

If char *p="hello".

P have an address of h only.

Whenever * and & comes we just need to simply cancel.

for e.g
p=10;
q=&p;
t=*&p--->means t=p

And if we print *&p it will print 10.

Very helpful, Thanks everyone.

Thumb Rule for pointers:

'*' and '&' are like 'x' and '1/x', so will cancel each other whenever place together.

Hope this makes it simple to understand.

Ans:[B] Because:

Given p="hello"

p=*(&p)=*&p

p=*&p=*(&(*&p))

p=*&*&p=hello

Best answer @Deepu.

I believe your answer is the only correct logic, because if we go by earlier mentioned logic's then it should print p where p stores the address of "Hello".

Thanks.

Because * is called dereference and & is called reference so * is cancel with &.