C Programming - Pointers - Discussion

This C code snippet demonstrates the use of pointers and functions. Here's a clear and concise explanation:

Header Inclusion: The code begins with #include<stdio.h>, which includes the standard input-output library necessary for using functions like printf.

Main Function: The main() function is the entry point of the program. Inside it:

An integer pointer j is declared (int *j;).

A function prototype for fun is declared, which takes a pointer to a pointer to an integer (void fun(int**);).
The fun function is called with the address of j (fun(&j);), passing a pointer to the pointer j.
Function Definition: The fun function is defined to accept a double pointer (int **k). Inside this function:

An integer variable a is initialized with the value 10.
The comment /* Add a statement here */ indicates where additional code can be added to manipulate or use the variable a or the pointer k.

Key Concepts:
Pointers: j is a pointer to an integer, and k is a pointer to a pointer to an integer. This allows for dynamic memory management and manipulation of variables at different levels of indirection.

Function Parameters: The function fun can modify the pointer j indirectly through the pointer k.

Example of Adding a Statement:
If you wanted to assign the value of a to the location pointed to by k, you could add the following line in the fun function.

**k will store value, whereas *k will store address.

Because int **k is pointer to pointer to the integer. When we apply once * on k we will get an address and on applying * second time on k we get value at (*k) address.

Because a is only the name of the variable at which actual value is stored i.e. 10.

And to access 10 from a location we use its address in this fun i.e &a.

By passing &j as argument,k has the address of j. *k is the value stored at j.so assignment statement *k=&a, stores address of a as value of j.

Its normal pointer assignment, whn fun is called its received as k, so whatever operation performed on k will be returned at j in main.

Simple, k contains address of j that is &j
*k = &a means *(&j) = &a
So finally j = &a.

AFTER DUNC CALL,
&J=**K;
J=*K;
IN FUNC FUN,
*K=&A;
SO,
J=&A;
SO ADDRESS OF A IS IN J

&J=**K
So, j=*K

We are assigning address of a to j.
So , J=&a
i.e *k=&a

Please anyone explain about /* add a statement here */.

I want to see the output.

But there is no semicolon after the statement in the answer?