C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 11)
11.
What will be the output of the program?
#include<stdio.h>

int main()
{
    int arr[2][2][2] = {10, 2, 3, 4, 5, 6, 7, 8};
    int *p, *q;
    p = &arr[1][1][1];
    q = (int*) arr;
    printf("%d, %d\n", *p, *q);
    return 0;
}
8, 10
10, 2
8, 1
Garbage values
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
58 comments Page 5 of 6.

Tanveerkhan guttal said:   1 decade ago
Nicely explained by Teklit Ehiopia.

Satishp said:   1 decade ago
a[0][0][0]=10;
a[0][1][1] =2;

0 1 ->blocks
0 1 0 1 ->sub blocks
10 2 3 4 5 6 7 8 ->values
0 1 0 1 0 1 0 1 ->sub blocks of sub blocks

3-D REPRESENTATION OF ARRY IS

blocks-subblocks-subblocks of subblocks-values
then a [0] [1] [1] = 4
a [1] [1] [0] = 7 .so i think it is correct.

Subhi said:   1 decade ago
Nicely explained by Teklit Ehiopia.

Mani said:   1 decade ago
Thanks for the clear explanation raghul

Pooja said:   1 decade ago
Thanks Rahul.

Naveen said:   1 decade ago
a[0][1][1] this means 1st block 2nd row 2nd coloumn right. ? its valus is 4. Am I right. ? please explain.

Subaa said:   1 decade ago
Nice explained chettan thank you.

Azagumozhi.M said:   9 years ago
@Teklit. Clear explanation.

HarshaN said:   1 decade ago
@shubham

No need of casting here as q in an integer point here.So q = (int*) arr; and q = arr; would result in same output.

J G Deepak said:   1 decade ago
1. a[1][1][1] is the last element. So a[1][1][1]=8.
2. The pointer *q always points to the first element of the array arr[][][], because of the initialization of q = (int*) arr. So *q represents the first element of the array.

Therefore the answer is 8,10.


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