C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 11)
11.
What will be the output of the program?
#include<stdio.h>

int main()
{
    int arr[2][2][2] = {10, 2, 3, 4, 5, 6, 7, 8};
    int *p, *q;
    p = &arr[1][1][1];
    q = (int*) arr;
    printf("%d, %d\n", *p, *q);
    return 0;
}
8, 10
10, 2
8, 1
Garbage values
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
58 comments Page 1 of 6.

RAHUL SHARMA said:   1 decade ago
Here the 3-D array the value can be store as:

a[2][2][2]={
{
10,2
3,4 // First Block
}
{
5,6
7,8 //Second Block
}
}
a[ 0 ] [ 0 ] [ 0 ] =10;
| | |
Block Rows Columns

a [ 1 ] [ 1 ] [ 1 ] = 8;
| | |
2'Block 2'Row 2'column


and the *arr represent the first number of a array is 10.


Then hence the number is (8,10).
(38)

Kishor said:   1 decade ago
Elements stored as:

arr[0][0][0] = 10
arr[0][0][1] = 2
arr[0][1][0] = 3
arr[0][1][1] = 4
arr[1][0][0] = 5
arr[1][0][1] = 6
arr[1][1][0] = 7
arr[1][1][1] = 8

So *p=arr[1][1][1]=8.

And *q=10(first element).
(4)

Chetan said:   1 decade ago
arr[2][2][2], this array representation says that there are 2Blocks each with 2Rows and 2Columns

i,e we can judge that every Block will have 4 Elements each
so Block1-------[10 2 3 4]
i,e {10 2} in Row1
{3 4} in Row2
Again, Block2----[5 6 7 8]
i,e {5 6} in Row1
{7 8} in Row2

Now, let me explain how elments are described in 3D array representaion:- [Block][Row][Column]
so, the member of Block1 are described as below,
10 is [0][0][0]
2 is [0][0][1]
3 is [0][1][0]
4 is [0][1][1]
now, the members of Block2,
5 is [1][0][0]
6 is [1][0][1]
and so on
Thus, arr[1][1][1] is 8
(2)

Punit said:   10 years ago
Why the statement q = (int*) arr? Why this type casting is done?
(1)

Shyamal said:   5 months ago
[2][2][2]=8 position
[1][1][2]=1 position
Answer is 8,10.
(1)

ArunKumar A said:   10 months ago
@All.

arr[0][0][0]={10, 2};
arr[0][0][1]={3, 4};
arr[0][1][1]={5, 6};
arr[1][1][1]={8, 0};
(1)

Anmol singh said:   1 year ago
Can anyone help me how 8 came? Anyone, please explain.
(1)

Nik said:   4 years ago
Thanks @Rahul.
(1)

Deepak said:   6 years ago
Can anyone explain this more clearly to get this?
(1)

Arvindh said:   1 decade ago
I feel the best way to think of 3D arrays is to imagine a cube and put the numbers in their corresponding vertices.

For 2x2x2 array, we can imagine a cube with a total of 8 vertices, 4 in the front and 4 at the back.

10, 2, 3, 4, 5, 6, 7, 8 can be written here as

10(5) 2(6)
3(7) 4(8)

/*
Where the numbers without brackets are the vertices of the nearer face of the cube and those in brackets are the vertices of the farther face.
*/

Now, a[1][1][1] is the bottom right vertex of the farther face of the cube -- which is 8.

And "arr" is the address of the first element of the array -- here it is 10.

So, we get 10 and 8 as the answers.
(1)


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