C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 23)
23.
If the size of integer is 4bytes, What will be the output of the program?
#include<stdio.h>
int main()
{
int arr[] = {12, 13, 14, 15, 16};
printf("%d, %d, %d\n", sizeof(arr), sizeof(*arr), sizeof(arr[0]));
return 0;
}
Discussion:
22 comments Page 1 of 3.
Pondey Ramu said:
2 decades ago
The array elements are 5 and the size is 4 then multiplying both we get 20 that is the size of the array and second one is size of the each array element and third one is size of the first array element that is 4 only thats why anwer 20,4,4
PRADEEP said:
2 decades ago
Thank you.
N prathyusha said:
2 decades ago
The array elements are 5 each of size 4 bytes so it is 20.
Where as second is size of addres not the individual element so the size of int as declared is 4 so it is 4.
Then the final one is size of individual element i.e. size of first array element so it is 4.
Where as second is size of addres not the individual element so the size of int as declared is 4 so it is 4.
Then the final one is size of individual element i.e. size of first array element so it is 4.
Pradip somase said:
2 decades ago
Thank you Pondey Ramu for description.
Srinivas.L said:
1 decade ago
The array elements are 5 each of size of 5 bytes. So it is 20.
Where as the second one is it will prints the address to store the int data type array so its value is 4.
And in last one is also it will prints the address of the arr[0], which is integer data type so its value is 4. So the final answer is 20 4 4.
Where as the second one is it will prints the address to store the int data type array so its value is 4.
And in last one is also it will prints the address of the arr[0], which is integer data type so its value is 4. So the final answer is 20 4 4.
Viraj said:
1 decade ago
Output will be 10 2 2 on 16 bit compiler.
Narendra said:
1 decade ago
The array elements are 5 each of size of 4 bytes. So it is 20,
where as second one is sizeof(*arr) means i.e pointer .all pointers occupies 4 bytesin 32 bit compiler so it is 4 bytes
and last one is same.
In 16 bit compiler it is 10 2 2;
where as second one is sizeof(*arr) means i.e pointer .all pointers occupies 4 bytesin 32 bit compiler so it is 4 bytes
and last one is same.
In 16 bit compiler it is 10 2 2;
Nirlep said:
1 decade ago
Why multiply by 4 it should be 2?
K SURESH said:
1 decade ago
THANK YOU PRATHYUSHA
Soumya said:
1 decade ago
Thank you pondey ramu.
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