C Programming - Input / Output - Discussion
Discussion Forum : Input / Output - Point Out Errors (Q.No. 4)
4.
Point out the error in the program?
#include<stdio.h>
/* Assume there is a file called 'file.c' in c:\tc directory. */
int main()
{
FILE *fp;
fp=fopen("c:\tc\file.c", "r");
if(!fp)
printf("Unable to open file.");
fclose(fp);
return 0;
}
Answer: Option
Explanation:
The path of file name must be given as "c:\\tc\file.c"
Discussion:
7 comments Page 1 of 1.
Vishal said:
1 decade ago
It crashes at run time. As the fp is NULL and its being passed to fclose.
Pravin said:
1 decade ago
If we write the path as given in explanation then option A will be the ans?
Bhushan said:
10 years ago
The program running successfully. The explanation was given wrong.
Vijay said:
10 years ago
Why should we give path name as c:\\tc\file.c?
Rohan said:
9 years ago
Program running successfully. There is no problem with the syntax of given path and extension but I don't logic of this if (! fp) ;.
Apoorva said:
9 years ago
c:\ tc\file.c is incorrect way of reading because when drive is specified like c,d etc .file path should be c:\\tc\file.c.
So, fp contain 0 value. if(!fp) means complementing fp content .if (condition) if statement falls only for 0.
Here if(!fp) becomes true so "Unable to open file" will be printed.
So, fp contain 0 value. if(!fp) means complementing fp content .if (condition) if statement falls only for 0.
Here if(!fp) becomes true so "Unable to open file" will be printed.
Shree said:
8 years ago
The Application will crash as mentioned by Visual.
int main()
{
FILE *fp;
fp = fopen("c:\tc\file.c", "r");
if(!fp)
printf("Unable to open file.");
else
fclose(fp);
return 0;
}
int main()
{
FILE *fp;
fp = fopen("c:\tc\file.c", "r");
if(!fp)
printf("Unable to open file.");
else
fclose(fp);
return 0;
}
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