C Programming - Input / Output - Discussion

Discussion Forum : Input / Output - Find Output of Program (Q.No. 6)
6.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    printf("%c\n", ~('C'*-1));
    return 0;
}
A
B
C
D
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 1 of 4.

Digvijay said:   3 years ago
ASCII value of 67 is (01000011).

67*-1= -67.


In C negative values are treated with 2's complement so its 1's complement is 10111100 + 1.
Its 2's complement is 10111101.

Now apply ~ to its 2's complement.

Therefore it becomes- 01000010.
It's the ASCII value of B(66).
(7)

Noureen said:   7 years ago
Very well explained, Thanks @Mohd Pv Vanimal.

Mohd pv vanimal said:   7 years ago
include<stdio.h>
int main()
{
printf("%d\n", 'C'); //67
printf("%d\n", 'C' * -1); //-67
printf("%d\n", ~('C' * - 1)); //66
printf("%c\n",~('C' * -1)); //B
return 0;
}

In 2's complement, the value of ~(-67) is 66.
(2)

Mayank said:   8 years ago
Very nice explanation @Vallabh.

Pallavi said:   8 years ago
Agree @Venkat.

Aminul said:   8 years ago
Yes, Right @Venkat.

Jayant said:   8 years ago
You are right @Vallabh.

Rahul said:   9 years ago
Thank you all for such a wonderful help. It is very helpful.

Alok said:   9 years ago
@Vallabh is correct.

Sowmiya said:   9 years ago
How ~67 comes to 66? Can someone explain please.


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