C Programming - Input / Output - Discussion

Discussion Forum : Input / Output - Point Out Errors (Q.No. 2)
Point out the error in the program?

int main()
    char ch;
    int i;
    scanf("%c", &i);
    scanf("%d", &ch);
    printf("%c %d", ch, i);
    return 0;
Error: suspicious char to in conversion in scanf()
Error: we may not get input for second scanf() statement
No error
None of above
Answer: Option
No answer description is available. Let's discuss.
23 comments Page 2 of 3.

Sowmiya said:   7 years ago
The 'i' is an integer type. So %d should be used and 'ch' is a character type so %c or %s should be used.

Ivon said:   8 years ago
But why I use CodeBlock (GCC compiler) to get it compiled and each scan runs smoothly, just getting wrong value, but it just got value for each place!

Shivam said:   9 years ago
Nice question!

[B]. Error: We MAY not get input for second scanf() statement.


-If you enter a character for first scanf, you are allowed to enter a value for second scanf.

-If you enter an integer for first scanf, you are not allowed to enter a value for second scanf.

Answer is simple just try think harder in memory size differences between int and char :).

Shivi said:   9 years ago
Because %d is a format specifier of int type but ch is a char data type.

Dinesh said:   10 years ago
I executed this program in Dev c++.

int main()
char i;
return 0;

Program compiled and executed successfully (Without any warning and errors).

Input provided : 65
Output : i==A

Nilay Vishwakarma said:   1 decade ago
There can't be any segmentation fault in this program
ch would store ASCII 10 (return or line feed).

Try cleaning buffer before entering next value since <return> would be in buffer and gets stored in next scanf.

@Himanshu Bansal.
Your point is almost correct, theoretically. However,we can store integer value inside character value, but there would be a slight ,malfunction. The least significant bits of the integer would be accepted as character.

The apple has fallen very far dude.

Himanshu Bansal said:   1 decade ago
You can store the character value inside integer value because character is of 1 byte and integer is 2 byte but you can not store integer value inside character value.

Rup said:   1 decade ago
'i' is an integer type so %d should be used and 'ch' is a character type so %c or %s should be used.

Shoana Carvalho said:   1 decade ago
What I guess is segmentation fault occurs only when there is buffer overflow comes into existence because of too many function calls!

Khushi said:   1 decade ago
No its not the case.

It will take input but the values that will get stored will be unexpected and it may lead to segmentation fault as well.

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