C Programming - Input / Output - Discussion

FILE *ptr;

Step 1: A pointer ptr is created for FILE

char i;

Step 2: A variable i is declared as character...

ptr = fopen("myfile.c", "r");

Step 3: ptr is used to store the content of "myfile.c" which is opened in readable mode..

while((i=fgetc(ptr))!=NULL)
printf("%c", i);

Step 4: (i) while loop is used , when an EOF is encountered fgetc() returns EOF.
(ii) Instead of checking the condition for EOF we have checked it for NULL.


Ans ->> [c] infinite loop.

Its coming segmentation fault for me.

Compilation:
temp.c: In function \'main\':
temp.c:8:25: warning: comparison between pointer and integer [enabled by default]
while((i=fgetc(ptr))!=NULL)

Running:
Segmentation fault (core dumped)

@Niyati.

Here we are accessing file from read mode ("r").
So the value accessed is printing on the screen, not into the file.
If you want to print (write) into the file then you should open in "w" mode.

On failure file returns EOF so, here we are checking up to NULL, so, up to NULL, it will take. Because after that no content will be there in a file for checking.

Correct me, If I am Wrong.

It depends upon contents of the file.

If the file contains NULL.

Then the o/p is.

Print the contents of file "myfile.c" up to NULL character.

Otherwise infinite loop.

What if the file has a NULL character in it? Then the correct answer would be option B. The content of the file should be displayed with the question.

According to me output depends upon the contents of file if it encounters null character than it will terminate else there will be infinite loop.

We are opening file in read mode then how is it possible to access the file contents(printing the contents of this file)?

If Null comes before some text and Eof I think It will execute upto Null.

"I Want to run" "I want" will get printed.

What if actually have a NULL character in our file somewhere in between? Please tell me.