C Programming - Functions - Discussion

#include<stdio.h>

int main()
{
int i=3, j=4, k, l;
k = addmult(i, j);
l = addmult(i, j);
printf("%d %d\n", k,l);
return 0;
}

int addmult(int ii, int jj)
{
int kk, ll;
kk = ii + jj;
ll = ii * jj;
return(kk);
return(ll);
}

If the program is rewritten as shown above the output is 7 7 how is it possible?

Can any one explain me please?

Comma (,) operator has left to right associativity, so while returning the rightmost operator will be returned and no error because of this.

int i=3, j=4, k, l;
k = addmult(i, j);
l = addmult(i, j);

A function cannot return two values at a time, k and l.

Hence it an compiler error.

Only return (kk) is being executed each time.

Coma (,) operater has right to left associativity, not to left to right.

The Comma Operator (,):

The comma operator, written as a comma (,) takes two operands. It evaluates its left operand and discards the value. It then evaluates its right operand, and returns that value as the result of the expression.

7 + 3, 6 * 2 // Gives 12
3,14 // Gives 14 (and not pi)

The comma operator is seldom necessary, except in function-like preprocessor macros, which we advise against anyway.

The commas used to separate the arguments in a call to a method, or the elements in an array, are not comma operators.

Very nice explanation! sundar.

Have a nice day.

Thanks sundar.

Answer is right, here it will return last return value.

If function is returning return(i,j); then value of j will return.

@ Preethi,,,,,we can return only one value in fuctions if we are not using pointer,,,,,,so when k==addmui(i,j); executes functions is called and and kk is returned fromreturn(kk),and recieved by k,now we cant return two statement so curser goes to main();
again l=admull(i,j);
again kk is retun boy time
hence you are feting to 7; ; ;ie7,7 or 77