C Programming - Functions - Discussion
Discussion Forum : Functions - Find Output of Program (Q.No. 19)
19.
What will be the output of the program?
#include<stdio.h>
int fun(int i)
{
i++;
return i;
}
int main()
{
int fun(int);
int i=3;
fun(i=fun(fun(i)));
printf("%d\n", i);
return 0;
}
Answer: Option
Explanation:
Step 1: int fun(int); This is prototype of function fun(). It tells the compiler that the function fun() accept one integer parameter and returns an integer value.
Step 2: int i=3; The variable i is declared as an integer type and initialized to value 3.
Step 3: fun(i=fun(fun(i)));. The function fun(i) increements the value of i by 1(one) and return it.
Lets go step by step,
=> fun(i) becomes fun(3) is called and it returns 4.
=> i = fun(fun(i)) becomes i = fun(4) is called and it returns 5 and stored in variable i.(i=5)
=> fun(i=fun(fun(i))); becomes fun(5); is called and it return 6 and nowhere the return value is stored.
Step 4: printf("%d\n", i); It prints the value of variable i.(5)
Hence the output is '5'.
Discussion:
17 comments Page 1 of 2.
Srinivas said:
1 decade ago
fun(i = fun(fun(i)));
Becomes fun(5); is called and it return 6 and nowhere the return value is stored.
Why it is not returning the value 6 can one please tell me?
Becomes fun(5); is called and it return 6 and nowhere the return value is stored.
Why it is not returning the value 6 can one please tell me?
Ketan said:
1 decade ago
fun(i=fun(fun(i)))
i is 3.
So,
fun(i=fun(fun(3)))
i.e. fun(i=fun(4))
i.e. fun(i=5)
So here i is assigned 5.
So 5 will get printed.
i is 3.
So,
fun(i=fun(fun(3)))
i.e. fun(i=fun(4))
i.e. fun(i=5)
So here i is assigned 5.
So 5 will get printed.
(1)
Sahil Ahmed said:
1 decade ago
Won't it give an Lvalue required error?
Rav said:
1 decade ago
I don't agree with the reason of @Ketan. Its wrong in my opinion. Why is it not returning? Can you explain?
Fajal said:
1 decade ago
But when there is fun (i=5) the function again gets called and it returns 6. So according to my point of view the answer is 6. Can anyone explain how it is 5.
Ishita said:
1 decade ago
As there is no such variable in which value 6 returned can be stored. So answer is 5. As we have to print value of i.
Abhinav said:
1 decade ago
Output will be 5 only because of fun (i=5), here 5 is stored in I so output is 5. If the question would have been like:
i = fun (i=fun(fun(i))); then the output will be 6.
i = fun (i=fun(fun(i))); then the output will be 6.
Chetan Kulkarni said:
10 years ago
Its error, when it calls fun (i=5). It needs a variable on left side. It should give L value required error.
OMKAR GURAV said:
10 years ago
I agree with @Chetan and @Sahil. Why the L value required error won't be there?
Swathi said:
9 years ago
#include<stdio.h>
int fun(int i)
{
i++;
return i;
}
int main()
{
int fun(int);
int i=3;
printf("%d\n", fun(i=fun(fun(i))));
printf("%d\n", i);
return 0;
}
In this, you will get the output near the first printf is 6,
and near second printf it is 5,
first 5 is assigned to i in main function so i will become 5.
After that, we are calling fun(5)
Here we are not collecting return value so in fun(5) i will become 6 but i is local to that function only so that variable life is end with that function life.
int fun(int i)
{
i++;
return i;
}
int main()
{
int fun(int);
int i=3;
printf("%d\n", fun(i=fun(fun(i))));
printf("%d\n", i);
return 0;
}
In this, you will get the output near the first printf is 6,
and near second printf it is 5,
first 5 is assigned to i in main function so i will become 5.
After that, we are calling fun(5)
Here we are not collecting return value so in fun(5) i will become 6 but i is local to that function only so that variable life is end with that function life.
(1)
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