C Programming - Floating Point Issues - Discussion

Discussion Forum : Floating Point Issues - Find Output of Program (Q.No. 4)
What will be the output of the program?
int main()
    printf("%f\n", sqrt(36.0));
    return 0;
Error: Prototype sqrt() not found.
Answer: Option

printf("%f\n", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000).

Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number.

15 comments Page 1 of 2.

Gaurav said:   1 decade ago
But sir, float has only 4 terms after decimal place and there is 6 six terms after decimal?

Ramkrishna said:   1 decade ago
6.0 is allso float right? Why can't I become a answer please explain?

Rajaasekaran said:   1 decade ago
Can you give me example program for square root of double ?

Surbhi said:   1 decade ago
Why not 6.0?

Shailesh said:   1 decade ago

36.0 is double.

6.0 is float.

So the answer 6.0 is not possible.

D SURESH said:   1 decade ago
Generally float value will display like six digits after the decimal point so, output of the above program will be 6.000000 because sqrt (36.0) =6.000000.

Sankari said:   1 decade ago
36.0 is double, how it is double can anyone explain me please?

What is double and float?

Nishant said:   1 decade ago
But when I tried in turbo C it return 0. Why?

Yogesh tiwari said:   1 decade ago
Sir I am not satisfied with your answer, it turbo c it create error please explain.

Meghana said:   9 years ago
Can anyone explain me how 36.0 is double?

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