C Programming - Floating Point Issues - Discussion
Discussion Forum : Floating Point Issues - Find Output of Program (Q.No. 9)
9.
What will be the output of the program?
#include<stdio.h>
int main()
{
float d=2.25;
printf("%e,", d);
printf("%f,", d);
printf("%g,", d);
printf("%lf", d);
return 0;
}
Answer: Option
Explanation:
printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 2.25 as 2.250000e+000.
printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 2.25 as 2.250000.
printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 2.25 as 2.25.
printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints the 2.25 as 2.250000.
Discussion:
8 comments Page 1 of 1.
Rohit mundhe said:
5 years ago
math.h is not included. How the program will run?
Harshad said:
9 years ago
Any words are remaining than tell me about it?
Kritika said:
9 years ago
For long double float we simply write %l whereas %lf is not allowed as said in previous answers so how could option C be the answer?
Ripal said:
1 decade ago
Why answer B is not correct? when you are using %f then it will print 2.25f in this program.
Kaushik said:
1 decade ago
main()
{
float a=4.24l; /*l is for long double in declaration and printf("%Lf",a); defination of a*/
} /*I am getting some weird result*/
{
float a=4.24l; /*l is for long double in declaration and printf("%Lf",a); defination of a*/
} /*I am getting some weird result*/
Dimple kamboj said:
1 decade ago
What is use of %g and %lf?
Raghav Naganathan said:
1 decade ago
@Rahul...%g is used for removing the insignificant zeroes after the mantissa of a decimal number.
eg. 2.250000 is reduced to 2.25.
what it basically does is it gives the decimal number without the insignificant zeroes.
Hope this helps.
eg. 2.250000 is reduced to 2.25.
what it basically does is it gives the decimal number without the insignificant zeroes.
Hope this helps.
Rahul said:
1 decade ago
Tell me more about %g.
(1)
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