C Programming - Expressions - Discussion
#include<stdio.h>
int main()
{
char ch;
ch = 'A';
printf("The letter is");
printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch);
printf("Now the letter is");
printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A');
return 0;
}
Step 1: char ch; ch = 'A'; here variable ch is declared as an character type an initialized to 'A'.
Step 2: printf("The letter is"); It prints "The letter is".
Step 3: printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch);
The ASCII value of 'A' is 65 and 'a' is 97.
Here
=> ('A' >= 'A' && 'A' <= 'Z') ? (A + 'a' - 'A'):('A')
=> (TRUE && TRUE) ? (65 + 97 - 65) : ('A')
=> (TRUE) ? (97): ('A')
In printf the format specifier is '%c'. Hence prints 97 as 'a'.
Step 4: printf("Now the letter is"); It prints "Now the letter is".
Step 5: printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A');
Here => ('A' >= 'A' && 'A' <= 'Z') ? ('A') : (A + 'a' - 'A')
=> (TRUE && TRUE) ? ('A') :(65 + 97 - 65)
=> (TRUE) ? ('A') : (97)
It prints 'A'
Hence the output is
The letter is a
Now the letter is A