C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 10)
10.
What is the output of the program?
#include<stdio.h>
int main()
{
union a
{
int i;
char ch[2];
};
union a u;
u.ch[0] = 3;
u.ch[1] = 2;
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
return 0;
}
Answer: Option
Explanation:
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); It prints the value of u.ch[0] = 3, u.ch[1] = 2 and it prints the value of u.i means the value of entire union size.
So the output is 3, 2, 515.
Discussion:
78 comments Page 4 of 8.
Aaryan said:
8 years ago
Hi friends, some guys have a problem that how we got a 512?
So the answer is like.
From right to left start from 1 and double the size after ++.
For eg...... 512 256 128 64 32 16 8 4 2 1
Binary is = 00000010 00000011.
512*1+0+0+0+0+0+0+0+2*1+1*1.
=512+2+1.
=515.
So the answer is like.
From right to left start from 1 and double the size after ++.
For eg...... 512 256 128 64 32 16 8 4 2 1
Binary is = 00000010 00000011.
512*1+0+0+0+0+0+0+0+2*1+1*1.
=512+2+1.
=515.
Ayush said:
9 years ago
How can we get the size of the entire union by u.i?
Preethi said:
8 years ago
Why we find the size of the union in coding doesn't mention about size only the variable value?
Yamani said:
8 years ago
Thank you for your explanation. It helps me a lot @Nandini.
Anonymous said:
9 years ago
If u.i displays the size of the Union then how to display the 'i' value?
Anonymous said:
9 years ago
Why u. i prints the size of the Union in the first place?
Can anyone answer it? please.
Can anyone answer it? please.
Prakash said:
9 years ago
Could anyone please explain me the output of this program?
#include<stdio.h>
int main()
{
union a
{
int i;
char ch;
};
union a u;
printf("%d,%f\n",sizeof(u),u.i);
return 0;
}
o/p: 4 23
#include<stdio.h>
int main()
{
union a
{
int i;
char ch;
};
union a u;
printf("%d,%f\n",sizeof(u),u.i);
return 0;
}
o/p: 4 23
Ritika said:
1 decade ago
Please explain in detail why is it giving 515 as the size of the union?
Deepika said:
9 years ago
union a u;
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
Can anyone explain these both lines?
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
Can anyone explain these both lines?
Radhika said:
1 decade ago
But why do u.i gives the size of union?
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