C Programming - Declarations and Initializations - Discussion

Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 10)
10.
What is the output of the program?
#include<stdio.h>
int main()
{
    union a
    {
        int i;
        char ch[2];
    };
    union a u;
    u.ch[0] = 3;
    u.ch[1] = 2;
    printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
    return 0;
}
3, 2, 515
515, 2, 3
3, 2, 5
None of these
Answer: Option
Explanation:

printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); It prints the value of u.ch[0] = 3, u.ch[1] = 2 and it prints the value of u.i means the value of entire union size.

So the output is 3, 2, 515.

Discussion:
78 comments Page 3 of 8.

Bhushan said:   1 decade ago
How we can calculate the value of u(I) at memory block 512?

Komal said:   1 decade ago
ch is char type of variable then how can we assign it number?

Sjohnson said:   8 years ago
@All.

If sizeof(int) > 4 then the upper bits of a.i is not initialized and the value of u.i can be greater than 0x0203. For example, the 64-bit compiler on my system produces the value 0x7c0203.

However, if I set u.i = 0 before setting u.ch[0], u.ch[1] then it works.

Khairul Islam said:   2 months ago
@All.

Here i = ch[1]*256 + ch[0].

Jayakumar v said:   4 years ago
Good explanation. Thanks, everyone.

Mesi said:   6 years ago
What will be the result if we add one more value u.ch[2]=4?

Mahesh said:   6 years ago
How that I and other two char arrays are related ?

We are asked to find I and how we are relating it with other variables.

Harika said:   6 years ago
Can anyone explain the memory allocation?

Please.

Saila said:   7 years ago
Thank you @Mostafa Hamoda.

Ajay gupta said:   7 years ago
@All.

As explained that how it became 515 and I understood it. But why we need to calculate the size of the union while we are accessing the value of the variable I in the union u. why the size and how u, I is related to the size.


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