C Programming - Declarations and Initializations - Discussion

Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 7)
7.
What is the output of the program
#include<stdio.h>
int main()
{
    int x = 10, y = 20, z = 5, i;
    i = x < y < z;
    printf("%d\n", i);
    return 0;
}
0
1
Error
None of these
Answer: Option
Explanation:
Since x < y turns to be TRUE it is replaced by 1. Then 1 < z is compared and to be TRUE. The 1 is assigned to i.
Discussion:
37 comments Page 2 of 4.

Chitra said:   1 decade ago
I think <, > have equal priority and the = have lesser priority than <, >.

<, > assign the priority based on 1st come 1st order.

Manu sharma said:   1 decade ago
What if the program is like this:

main()
{
int a=4,b=2;
a=b<<a+b>>2;
printf("%d",a);
}

What will be the output?

Sai said:   1 decade ago
int main()
{
int x = 30, y = 20, z = 5, i;
i = x <y <z;
printf("%d\n", i);
return 0;
}

Please explain this program.

Mostafa said:   1 decade ago
@Mary,

If x>y>z then,

10>20 return false "0".

0>5 return false "0".

The output will be 0.

Anmol said:   1 decade ago
No that's an wrong answer. If returning type would be Boolean that it would have been an correct answer.

Nikhil said:   1 decade ago
@Shiva

Ans is 0 because x>y is false so its return 0 & 0>5 also false so ans is 0.

Deepu said:   1 decade ago
Ya < symbol have left associate. So, it complies from left to right.

The ans is "1".

Wikiok said:   1 decade ago
1. i=x<y<z
1. i=((10<20) < 5)
2. i=((1) < 5)
3. i=(1)

(True=1; False=0)

Richik said:   1 decade ago
What if one part is TRUE and another FALSE, what value of i will we take then?

Palak agrawal said:   1 decade ago
Yaa anyone tell the reason in above program. Why it is 10 not 20 or 30?


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