C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 7)
7.
What is the output of the program
#include<stdio.h>
int main()
{
int x = 10, y = 20, z = 5, i;
i = x < y < z;
printf("%d\n", i);
return 0;
}
Answer: Option
Explanation:
Since x < y turns to be TRUE it is replaced by 1. Then 1 < z is compared and to be TRUE. The 1 is assigned to i.
Discussion:
37 comments Page 1 of 4.
Loelynk said:
2 years ago
Hello guys,
10<20(absolutely this condition is true.
True are 1
False are 0
The first x<1
Y are 1(true), that's time 1<5.
The second condition is also true(1), that 1 is passing through i.
10<20(absolutely this condition is true.
True are 1
False are 0
The first x<1
Y are 1(true), that's time 1<5.
The second condition is also true(1), that 1 is passing through i.
(2)
Rohan said:
8 years ago
What if it is from right to left?
(1)
Agnes said:
8 years ago
10<20=false ===>0
0<5=true===>1
Hence the output 1.
0<5=true===>1
Hence the output 1.
(1)
Kanniyappan said:
9 years ago
Is it possible to compare flag value < 5?
Ssindham said:
9 years ago
Your Explanation is perfect @Wikiok.
Rishi said:
9 years ago
Y>z = 20>5 true 1 then 1>10.
False 0.
1 true 1 false.
False 0.
1 true 1 false.
Kumar Ajit said:
10 years ago
#include<stdio.h>
int main()
{
int x=10,y=20,z=5,i;
i=y>z>x;
printf("%d\n",i);
return 0;
}
Why out put is 0? I not understand friend explain it.
int main()
{
int x=10,y=20,z=5,i;
i=y>z>x;
printf("%d\n",i);
return 0;
}
Why out put is 0? I not understand friend explain it.
Richik said:
1 decade ago
What if one part is TRUE and another FALSE, what value of i will we take then?
Sneha said:
1 decade ago
Explain me before program.
Bis said:
1 decade ago
What is the use of this code?
(1)
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