C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - General Questions (Q.No. 2)
2.
What are the types of linkages?
Answer: Option
Explanation:
External Linkage-> means global, non-static variables and functions.
Internal Linkage-> means static variables and functions with file scope.
None Linkage-> means Local variables.
Internal Linkage-> means static variables and functions with file scope.
None Linkage-> means Local variables.
Discussion:
95 comments Page 8 of 10.
Ago balan said:
1 decade ago
int a; --> Here a is a variable of integer. We can increment the value of a using for loop.
static int a; --> Whenever 'a' is called at any line in a program 'a' value is assigned automatically that value is previous value of a we used sometime earlier in program. Actually static is storage class.
static int a; --> Whenever 'a' is called at any line in a program 'a' value is assigned automatically that value is previous value of a we used sometime earlier in program. Actually static is storage class.
Suresh said:
2 decades ago
What is static variable?
Vidya said:
1 decade ago
main() {
char str1[]="Hello";
char str2[]="Hello";
if ( str1==str2 )
printf("True");
else
printf("False");
}
ans:false
please explain the answer
char str1[]="Hello";
char str2[]="Hello";
if ( str1==str2 )
printf("True");
else
printf("False");
}
ans:false
please explain the answer
Gaurav said:
1 decade ago
@Praveen.
Why x++ value remains 2?
Why it is not incremented by 1?
Why x++ value remains 2?
Why it is not incremented by 1?
Jhansi said:
1 decade ago
Give details of linkages & when they are used?
Alok said:
1 decade ago
@Sonali see this one.
z=(++x)+(++x)
For 1st ++x, the value of x is first increased about one and then assign, that means the value of x changes from 5 to 6.
Its clear in the same way the 2 nd ++x, x changes from 6 to 7.
So, final value of x is 7.
That means z = x+x.
For 1st and 2nd x's the value is same that is 7.
Therefore Z = 7+7.
z=(++x)+(++x)
For 1st ++x, the value of x is first increased about one and then assign, that means the value of x changes from 5 to 6.
Its clear in the same way the 2 nd ++x, x changes from 6 to 7.
So, final value of x is 7.
That means z = x+x.
For 1st and 2nd x's the value is same that is 7.
Therefore Z = 7+7.
Sonali said:
1 decade ago
I'm still confuse in that z value, will it be 5 or 6? and how?
@Shibu and @ Praveen.
@Shibu and @ Praveen.
Praveen said:
1 decade ago
@Raju.
Begin from the right most(x++).
x++ -> value remains 2,
Now ++x -> 2 incremented to 3. now x contains the final value 3 but it can't assign post increment.
Hence z = 3+2 = 5.
Begin from the right most(x++).
x++ -> value remains 2,
Now ++x -> 2 incremented to 3. now x contains the final value 3 but it can't assign post increment.
Hence z = 3+2 = 5.
Rakhi said:
1 decade ago
What are linkage?
Amru said:
1 decade ago
What is the exact meaning of linkage? what exact it does. ?
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