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C Programming - Declarations and Initializations - Discussion

Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 4)
Declarations and Initializations
4.
What is the output of the program in Turbo C (in DOS 16-bit OS)? 
#include<stdio.h>
int main()
{
    char *s1;
    char far *s2;
    char huge *s3;
    printf("%d, %d, %d\n", sizeof(s1), sizeof(s2), sizeof(s3));
    return 0;
}
2, 4, 6
4, 4, 2
2, 4, 4
2, 2, 2
Answer: Option
Explanation:

Any pointer size is 2 bytes. (only 16-bit offset)
So, char *s1 = 2 bytes.
So, char far *s2; = 4 bytes.
So, char huge *s3; = 4 bytes.
A far, huge pointer has two parts: a 16-bit segment value and a 16-bit offset value.

Since C is a compiler dependent language, it may give different output in other platforms. The above program works fine in Windows (TurboC), but error in Linux (GCC Compiler).

Discussion:
55 comments Page 6 of 6.
Muthu said:   8 years ago
What is far, hug and why it has 4bytes?
Satya said:   9 years ago
The far and huge have the same value.
Ashwini Shirke said:   8 years ago
Why intially 2 byte output is come?
Jeyanthi said:   1 decade ago
I don't understand this.
Vinu said:   1 decade ago
What is far and huge?
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