C Programming - Declarations and Initializations - Discussion

Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 4)
4.
What is the output of the program in Turbo C (in DOS 16-bit OS)?
#include<stdio.h>
int main()
{
    char *s1;
    char far *s2;
    char huge *s3;
    printf("%d, %d, %d\n", sizeof(s1), sizeof(s2), sizeof(s3));
    return 0;
}
2, 4, 6
4, 4, 2
2, 4, 4
2, 2, 2
Answer: Option
Explanation:

Any pointer size is 2 bytes. (only 16-bit offset)
So, char *s1 = 2 bytes.
So, char far *s2; = 4 bytes.
So, char huge *s3; = 4 bytes.
A far, huge pointer has two parts: a 16-bit segment value and a 16-bit offset value.

Since C is a compiler dependent language, it may give different output in other platforms. The above program works fine in Windows (TurboC), but error in Linux (GCC Compiler).

Discussion:
55 comments Page 5 of 6.

Laxman said:   6 years ago
Sir every pointer has 2 bytes so how *s2, *s3 4 bytes?

Saraswathi said:   1 decade ago
Then what is huge pointer? is it same as far pointer.

Saranya said:   9 years ago
What is 16-bit segment value and 16-bit offset value?

Ranjith said:   2 decades ago
I don't know what is far and huge. Can you explain?

Kavita.C.Karjagar said:   1 decade ago
1.Explain what is far and huge?
2.were it is used?

Aruna said:   1 decade ago
Can anyone explain in detail about far and huge?

Sri said:   9 years ago
Why should we consider 4 for both far and huge?

Rohit said:   1 decade ago
How is the answer is 2, 4, 4 explain in depth ?

Pooja said:   10 years ago
Can anybody explain huge pointer in detail?

Baahubali said:   8 years ago
What is offset and segment in this case?


Post your comments here:

Your comments will be displayed after verification.