C Programming - Control Instructions - Discussion

int i=1
for(i=-1;i<=10;1++)
Then how it calculate -1 in for loop ?
Then how many it print?
Please explain this.

Can someone please tell me why the output is 27 for the following code?

#include<stdio.h>
int main()
{
int b=5;
int c= ((b++) + (++b) + (++b) + (++b));
printf("%d",c);
return 0;
}

True block evaluated continuously tat is (x<5)0,1,2,3,4 until 4<5 when 5<5 condition checked the condition bcm false then the control pass to else block which will break and exit. but if u want to print the given statement just write it upon the break statement it will print 1 time indiaBIX on ur output screen.

Good Ritesh...
In the above program the "IndiaBix" will be printed 12 times because...

At x= -1,0,1,2,3,4 i.e 6 times the condition x<5 is satisfied so the statement in the if block and the one after the block(in the loop level) will be printed... As both the statements are "indiaBix" it will be printed 12 times(6x2).......

After x=4 i.e at x=5,6,7... the condition x<5 is not satisfied so the control is transferred to else block which contains break; statement. here break; terminates the loop execution so nothing is printed after x=5.....

So only 12 times it is printed...

The "Continue" Statement Takes the control to the beginning of the loop,So When ever value of if(x<5) continue appreas,control goes to begining of loop and value of X is incremented.

"Break" Satatement takes the control out of the loop.So when it is occured,control is taken out of the Loop.

Thus "IndiaBix" Will never get printed.

control never goes to printf("IndiaBix"); statement.. So there exists compilation error.. Hence the solution is 0 times

Continue takes the control to the beginning of the loop. Therefore as far as x<5, nothing happens.

As soon as value of x is 5,break statement takes the control outside the loop body.

Will break and exit statements work similarly ?

If x is <5, if condition will executed, other 6 then loop process is terminated, then return 0 will occur, then final result get 0 times loop occur.

In the above program the "continue" statement is like

if (x < 5) continue;

this continue statement will take the compiler to continue without further steps and it will go for the "for loop" and it increment the i value until the condition like if (x = 5) and then the compiler execute the ELSE statement i.e. "break;" here the compiler will not reach the "print statement", so it will not execute the printf ("IndiaBIX") ;.