C Programming - Control Instructions - Discussion

Once if statement is false.

The control will move to the else block and the break statement.
Present in the else block will pass the control out of the body of the loop,

So nothing gets printed.

Here in the program, we have a integer variable. And a integer variable has the tendency to convert negative number. i.e. "signed number" into a positive no. i.e. "unsigned number". due to which the value -1 after converting into a positive no obviously becomes greater than 5 ;

And as there is a break statement after the 'else' statement the program terminates.

@Murugesan @Vipin dhawan.

I has little bit query you guys answered for @Rohit question.
When it is b++ there will be no change in the value.

for ++b the value get increased by 1.
OK.

Let us take you are right for a while then,
for(i=-1;i<10;i++)

In this case what will be occur? I mean what will happens here for i++ whether it will increase or won't change.

Here for(x=-1), therefore the IndiaBix is printed 0 times.

can anyone please explain me the output?

#include<stdio.h>
main()
{
int p=5;
printf(" %d %d %d ",p,p++,++p);
}

Output is, as per indiabix.com compiler is 7 6 7

Continue always takes the control back to the beginning of the loop and thus the value of x keeps on incrementing until it reaches the value 5. Once it becomes 5, the if condition fails and thus else comes into the picture. In the else block there is a break statement and hence entering into else makes the control to come come out of the for loop and point to the very next statement outside the for loop. Since there is no other printf statement. The whole of the program does not print IndiaBix.

We can not use continue with if statement.

Since the continue transfers the flow of program at the starting of the loop and break statement transfers the flow of program outside the loop it will be printed for 0 times.

#include<stdio.h>
int main()
{
int x;
for(x=-1; x<=10; x++)
{
if(x < 5) // here this is true for x=-1
continue;//so this is excuted
else //next this is executed
break;//the moment it reaches here, the break //statement gets the control out of for loop
printf("IndiaBIX");//so this statement not printed
}
return 0;
}

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So according to that it executes 0 times.

Let's think what's compiler reads this program.
Since when i<5 it skips the remaining part and when i>=5 it breaks the loop and exit the function. As no print command outside the loop so there is 0 times print, that's it.