C Programming - Control Instructions - Discussion

@Dumanth.

The correct solutions is Compiler assuming default all the declared values are in double value so, the first step initialize values to different data type then it will compile, the compiler takes it as double value even if it is any data type, and then compare a and b value both are equal. So the answer is "I LOVE YOU".

Here int is first promoted to float 3.0 and then the two values are compare which prints x and y are equal.

Hmm. I too tried it in compiler. It give "X and Y are equal".

How it possible?

Both are different data types. There should be apply type casting. But in this program it is not applicable. Can you clarified my doubt?

How an int value can be converted into float and compare automatically without using any comparative operator?

Decimal range between .0 to .5 is treated as float.

Example 3.5 is a float no need to write as 3.5f.

3.8 is double because its range greater than (see after decimal point) than .5 range so it is double.

I have checked all the values.

When there is no fractional part like int 3.0 and float/double=3.0 then both are same (type conversion occur).

When there is values like 3.1 or 3.2 like, there if no type conversion.

Also if we put float y=3.0f, then also both int and float are equal.

The output will be: x = 2, y = 3, z = 3.

Initially,

x = 4.

y = not assigned.

z = not assigned.

y = --x;

Performs a prefix decrements, so x will be 3 and y will be 3.

z = x--;

Performs a post-fix decrements operation so,

z = 3.

And x will decrements to 2 after being assigned to z.

Thus x = 2, y = 3, z = 3.

#include<stdio.h>
int main()
{
int x=4,y,z;
y=--x;
z=x--;
printf("x=%d y=%d z=%d\n",x,y,z);

return 0;
}

What will be the output? Please explain.

int x = 3;
float y = 3.000000111111;
if(x == y)
printf("x and y are equal");
else
printf("x and y are not equal");
return 0;

*************************************************

int x = 3;
float y = 2.9999999;
if(x == y)
printf("x and y are equal");
else
printf("x and y are not equal");
return 0;

Now check this out. In both case you will find the same result. From my point of view an implicit conversion of float type is done by compiler after a certain limit.

Since float is bigger datatype than int so it implicitly typecast int into float. That's why both the x and y of float type then the comparison is true.