C Programming - Control Instructions - Discussion

Why statement 2 is wrong?

We can check for ranges.

/*example*/
switch(a)
{
case 2:
case 3:
case 4:
/* some statements */
break;
case 5:
case 6:
case 7:
/* some statements */
break;
}

Can we wrote switch statement without cases? Please anyone tell me.

We can't check the ranges of non-integer values through switch statement, and so switch is not useful in checking the ranges of a number.

We can't check the ranges of non-integer values through switch statement, and so switch is not useful in checking the ranges of a number.

It is not necessary to use a break in every switch statement.

We use break in case statement not in switch.

Each and every case should have break condition. Whether it is mandatory?

We can use it but it is not efficient and hence not preferred. Instead we can use an if statement to check for a range of values.

Eg. to check whether value of variable x lies between 0 and 100.

1.switch-case

switch(x)
{
case 0:
case 1:
case 2:
.
.
.
.
case 99:
case 100:printf("True");break;
default: printf("False");break;
}

//This is very long and tedious and hence not useful. Instead we can Accomplish this in a few lines only using if statement.

2.if-else

if(x>=0 && x<=100)
printf("True");
else printf("False");

Yes, we can use switch for checking whether the given value falls under a range or not. So how can it be incorrect?

But the question is that why the 2nd option is incorrect even we can use switch to find range?

Hello
If v don't knw the ans...
by reading 4th option v say its 100% rit.
then check out of A B C D wch hav 4, so v got only B & C hav 4
so discard A&D now B hav 1 3 & C hav 2 Extra
Then read only 2nd option
if 2 is right then surely ans is C else
ans is 100% B.
Such typ Of technique is used for Finding the exactly correct ans in very short time.
thnx hav a nic day