C Programming - Control Instructions - Discussion
Discussion Forum : Control Instructions - Point Out Correct Statements (Q.No. 6)
6.
Which of the following statements are correct about the below C-program?
#include<stdio.h>
int main()
{
int x = 10, y = 100%90, i;
for(i=1; i<10; i++)
if(x != y);
printf("x = %d y = %d\n", x, y);
return 0;
}
| 1 : | The printf() function is called 10 times. |
| 2 : | The program will produce the output x = 10 y = 10 |
| 3 : | The ; after the if(x!=y) will NOT produce an error. |
| 4 : | The program will not produce output. |
Discussion:
70 comments Page 6 of 7.
Keerthana Sundaram said:
1 decade ago
Clear explanation. Thanks.
Sai said:
1 decade ago
1.Actually after "if" condition there is ;(semicolon) then it becomes an infinite loop.If condition calls itself again and again till termination i.e from 1 to 10.After terminating now control will go to printf.And printf will be called for last checking condition in "if"..
Aswin said:
1 decade ago
As We have got a ';' after if condition, it checks for equivalence of x & y for 10 times and executes the ';'.
As ';' in C is treated as a statement thats why every statement ends with a ';'.
and values of x and y are printed as 10 as they are not getting modified any where...
As ';' in C is treated as a statement thats why every statement ends with a ';'.
and values of x and y are printed as 10 as they are not getting modified any where...
Prashant said:
1 decade ago
1. Here x=10, y=10 because 100 % 90 means reminder after dividing 100 by 90 (that is modulo operation). So initialy x=10 and y=10.
2. Here for loop not have curly brases so default scope of for loop is next statement of for loop means for loop contains only one statement that is if(x!=y). So printf statement is not incuded in for loop. As the contol leave the for loop it comes to printf statement and it gets executed.
2. Here for loop not have curly brases so default scope of for loop is next statement of for loop means for loop contains only one statement that is if(x!=y). So printf statement is not incuded in for loop. As the contol leave the for loop it comes to printf statement and it gets executed.
Rekha said:
1 decade ago
Here in if(!x<y);
So program will execute sequentially i.e after if(!x<y);statement the control will goes successfully on next line which is printf statement hence it will no produce any error and produce output x=10 and y=10.
So program will execute sequentially i.e after if(!x<y);statement the control will goes successfully on next line which is printf statement hence it will no produce any error and produce output x=10 and y=10.
Shailendra said:
1 decade ago
Your concept is very clear Kavya
Dana said:
1 decade ago
2,3 comes how?
Aahana said:
1 decade ago
Since its given that x=10 and y=100%90 so the value of x will be 10 and value of y will be 10 remainder is considered in case of % operator . and since for loop does not have any scope i.e it does not contain any body so sequential execution will take place and the statement that x!=y is false inspite of that the printf statement will execute because because the condition x!=y is terminated by ;
Tabassum said:
1 decade ago
Initailly the value of x=10 and y=100%90 is provided
how u all can say that the value of y is also 10 can one exaplain how its possible becoz it is modulus and that will take only remainder into picture that means it is 1 right or i dont know can any one exaplain me this in more elaboration.
how u all can say that the value of y is also 10 can one exaplain how its possible becoz it is modulus and that will take only remainder into picture that means it is 1 right or i dont know can any one exaplain me this in more elaboration.
Bhushan said:
1 decade ago
Thanks kavya. !
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