C Programming - Control Instructions - Discussion
Discussion Forum : Control Instructions - Find Output of Program (Q.No. 16)
16.
What will be the output of the program?
#include<stdio.h>
int main()
{
int x = 10, y = 20;
if(!(!x) && x)
printf("x = %d\n", x);
else
printf("y = %d\n", y);
return 0;
}
Answer: Option
Explanation:
The logical not operator takes expression and evaluates to true if the expression is false and evaluates to false if the expression is true. In other words it reverses the value of the expression.
Step 1: if(!(!x) && x)
Step 2: if(!(!10) && 10)
Step 3: if(!(0) && 10)
Step 3: if(1 && 10)
Step 4: if(TRUE) here the if condition is satisfied. Hence it prints x = 10.
Discussion:
13 comments Page 1 of 2.
Navi said:
1 decade ago
Didn't get you. How if loop becomes true. ?
Sundar said:
1 decade ago
The following program with output will help you understand this problem clearly.
//Output:
2 is Evaluated to True.
-2 is Evaluated to True.
0.2 is Evaluated to True.
0 - Evaluated to False.
#include<stdio.h>
int main()
{
if(2) printf("2 is Evaluated to True. \n");
if(-2) printf("-2 is Evaluated to True. \n");
if(0.2) printf("0.2 is Evaluated to True. \n\n");
if(!0) printf("0 - Evaluated to False. \n");
return 0;
}//Output:
2 is Evaluated to True.
-2 is Evaluated to True.
0.2 is Evaluated to True.
0 - Evaluated to False.
Vignesh R said:
1 decade ago
Some one please help I cannot get this program.
Tufananand said:
1 decade ago
In if() condition, inside the parenthesis if we put any number like 1 2 3 etc. but not zero then in c language it is considered to be true.
Eg.
if(1)->true
if(5)->true
if(-7)->true etc.
But if(0)->false
Now compare this with above program. I hope you understand now.
Eg.
if(1)->true
if(5)->true
if(-7)->true etc.
But if(0)->false
Now compare this with above program. I hope you understand now.
Uma said:
1 decade ago
What is the meaning of if(!(0))? Please tell.
Msngs said:
1 decade ago
if(!(0))= if(1)->True
Vikky said:
1 decade ago
(!x) = (!10) = 0 how?
Pratyush said:
1 decade ago
@Vikky. '!' it is a logical not operator.
It works like this:
!(0) -> 1.
!(any non zero no.) -> 0.
!!(0) -> 0.
!!(any non zero no.) -> 1.
It works like this:
!(0) -> 1.
!(any non zero no.) -> 0.
!!(0) -> 0.
!!(any non zero no.) -> 1.
Jitender Chhirang said:
1 decade ago
Can't understand what do we mean by !(!x) double not and how will we read this loop statement.
Ramya said:
1 decade ago
Here if (! (!x) &&x) means !(10) = 0 next among!, && ! has highest priority.
Therefore !(0) means 1, 1&&10 means again 1 because any non zero number gives true and true&&true is true if(true) means true therefore true block is executed and x = 10 is printed.
Therefore !(0) means 1, 1&&10 means again 1 because any non zero number gives true and true&&true is true if(true) means true therefore true block is executed and x = 10 is printed.
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