C Programming - Control Instructions
Exercise : Control Instructions - Point Out Errors
6.
Point out the error, if any in the program.
#include<stdio.h>
int main()
{
int P = 10;
switch(P)
{
case 10:
printf("Case 1");
case 20:
printf("Case 2");
break;
case P:
printf("Case 2");
break;
}
return 0;
}
Answer: Option
Explanation:
The compiler will report the error "Constant expression required" in the line case P: . Because, variable names cannot be used with case statements.
The case statements will accept only constant expression.
7.
Point out the error, if any in the program.
#include<stdio.h>
int main()
{
int i = 1;
switch(i)
{
case 1:
printf("Case1");
break;
case 1*2+4:
printf("Case2");
break;
}
return 0;
}
Answer: Option
Explanation:
Constant expression are accepted in switch
It prints "Case1"
8.
Point out the error, if any in the while loop.
#include<stdio.h>
int main()
{
void fun();
int i = 1;
while(i <= 5)
{
printf("%d\n", i);
if(i>2)
goto here;
}
return 0;
}
void fun()
{
here:
printf("It works");
}
Answer: Option
Explanation:
A label is used as the target of a goto statement, and that label must be within the same function as the goto statement.
Syntax: goto <identifier> ;
Control is unconditionally transferred to the location of a local label specified by <identifier>.
Example:
#include <stdio.h>
int main()
{
int i=1;
while(i>0)
{
printf("%d", i++);
if(i==5)
goto mylabel;
}
mylabel:
return 0;
}
Output: 1,2,3,4
9.
Point out the error, if any in the program.
#include<stdio.h>
int main()
{
int a = 10, b;
a >=5 ? b=100: b=200;
printf("%d\n", b);
return 0;
}
Answer: Option
Explanation:
Variable b is not assigned.
It should be like:
b = a >= 5 ? 100 : 200;
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