C Programming - Const - Discussion
Discussion Forum : Const - Point Out Errors (Q.No. 2)
2.
Point out the error in the program (in Turbo-C).
#include<stdio.h>
#define MAX 128
int main()
{
const int max=128;
char array[max];
char string[MAX];
array[0] = string[0] = 'A';
printf("%c %c\n", array[0], string[0]);
return 0;
}
Answer: Option
Explanation:
Step 1: A macro named MAX is defined with value 128
Step 2: const int max=128; The constant variable max is declared as an integer data type and it is initialized with value 128.
Step 3: char array[max]; This statement reports an error "constant expression required". Because, we cannot use variable to define the size of array.
To avoid this error, we have to declare the size of an array as static. Eg. char array[10]; or use macro char array[MAX];
Note: The above program will print A A as output in Unix platform.
Discussion:
13 comments Page 1 of 2.
Mustafa said:
1 decade ago
In gcc compiler it is running fine, no warnings and errors.
Mms said:
1 decade ago
Can be build in data type as a variable name?
Narendar said:
1 decade ago
Yes it works fine in gcc because it is compiler dependent. What I meant to say is data type range.
Siva said:
1 decade ago
No friends here they declare the int type as const. Const can't change and he take only the constant variable. So char type need const.
Raj kumar said:
1 decade ago
In above program if we declare.
int max=128;
char array[max];
Without const then it works or not.
int max=128;
char array[max];
Without const then it works or not.
Mohammad Mohsin said:
10 years ago
Definitely it will print A.
Dilna vincent said:
10 years ago
Since we declare max as const int it should work.
Deepthi said:
10 years ago
It works fine no error. It prints A A.
Jaydip said:
10 years ago
On GCC its provides no error, and prints A A.
AMIN said:
9 years ago
Yes, option 'D' is correct answer.
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