C Programming - Complicated Declarations - Discussion
Discussion Forum : Complicated Declarations - Find Output of Program (Q.No. 8)
8.
What will be the output of the program in DOS (Compiler - Turbo C)?
#include<stdio.h>
double i;
int main()
{
(int)(float)(char) i;
printf("%d",sizeof(i));
return 0;
}
Discussion:
14 comments Page 2 of 2.
Ramanathan said:
1 decade ago
What is the difference between these two
(float) i; and
float i;
It produce the size as 8 and 4 respectively.?
(float) i; and
float i;
It produce the size as 8 and 4 respectively.?
Raj said:
1 decade ago
Initially i is declared as double. So i=8 .
Kickem said:
1 decade ago
In the line <(int)(float)(char) i;> the casts do not modify the type of the variable i, so i is still a Double stored 8 bytes.
Swathi said:
2 decades ago
Can any one explain this?
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