C Programming - Complicated Declarations
Exercise : Complicated Declarations - Find Output of Program
- Complicated Declarations - General Questions
- Complicated Declarations - Find Output of Program
- Complicated Declarations - Point Out Errors
- Complicated Declarations - True / False Questions
- Complicated Declarations - Yes / No Questions
6.
What will be the output of the program?
#include<stdio.h>
int main()
{
char huge *near *far *ptr1;
char near *far *huge *ptr2;
char far *huge *near *ptr3;
printf("%d, %d, %d\n", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3));
return 0;
}
7.
What will be the output of the program?
#include<stdio.h>
typedef unsigned long int uli;
typedef uli u;
int main()
{
uli a;
u b = -1;
a = -1;
printf("%lu, %lu", a, b);
return 0;
}
Answer: Option
Explanation:
The system will treat the negative numbers with 2's complement method.
For 'long int' system will occupy 4 bytes (32 bits).
Therefore,
Binary 1 : 00000000 00000000 00000000 00000001
To represent -1, system uses the 2's complement value of 1. Add 1 to the 1's complement result to obtain 2's complement of 1.
So, First take 1's complement of binary 1 (change all 0s to 1s and all 1s to 0s)
1's complement of Binary 1:
11111111 11111111 11111111 11111110
2's complement of Binary 1: (Add 1 with the above result)
11111111 11111111 11111111 11111111
In HexaDecimal
11111111 11111111 11111111 11111111 = FFFF FFFF FFFF FFFF
In Unsigned Integer
11111111 11111111 11111111 11111111 = 4294967295.
8.
What will be the output of the program in DOS (Compiler - Turbo C)?
#include<stdio.h>
double i;
int main()
{
(int)(float)(char) i;
printf("%d",sizeof(i));
return 0;
}
9.
What will be the output of the program under DOS?
#include<stdio.h>
int main()
{
char huge *near *far *ptr1;
char near *far *huge *ptr2;
char far *huge *near *ptr3;
printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3));
return 0;
}
10.
What will be the output of the program?
#include<stdio.h>
int main()
{
struct s1
{
char *z;
int i;
struct s1 *p;
};
static struct s1 a[] = {{"Nagpur", 1, a+1} , {"Chennai", 2, a+2} ,
{"Bangalore", 3, a} };
struct s1 *ptr = a;
printf("%s,", ++(ptr->z));
printf(" %s,", a[(++ptr)->i].z);
printf(" %s", a[--(ptr->p->i)].z);
return 0;
}
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