C Programming - Complicated Declarations - Discussion

@ALL.

Step 1: void display(int (*ff)()); ->a display is a function with a arguement as [*ff pointer function which is integer ] and its returns type of the function (display ) is void ..
int show();

Step 2: a function[ show() ] is declared as integer.

int (*f)();

Step 3: a pointer function [*f()] is declared as f.

f = show();

Step 4: It should store the content of show() function

display(f);

Step 5: displays the content of f.

void display(int (*ff)())
{
(*ff)();
}

Step 6: definition of the function[display]

int show()
{
printf("IndiaBIX");
}

Step 7: It will define the function show() and print IndiaBix.

void display(int (*ff)());
//display is a function that returns
//void. Its argument is a pointer to a function returning int.

int show(); //prototype declaration.

int (*f)();
//f is a pointer to a function returning int.
//This is to be used as argument to display.
//display simply calls the function passed as argument.
//Observe that this program allows us to call a function as
//argument to another function. This is possible only using pointers.

To Jessie.

In the given program int (*f) () ;, it clearly indicates that f is function pointer.

Any function name holds address of that function as we see in array, there array name holds base address of that array.

There by.

F=show; means the function pointer f is initialized to address of the show function. There is no error in this statement.

int (*f)();
f = show;
f is a pointer to the function replace f by show int (*show)(); So it was correct I guess.

There should be an error option because the return type of function show() is int but it is not returning anything.

But show is a function, then f = show how it can be possible?
It should be f=show(). So, here is an error.

Technically, the function show() should return a value, since it is declared [int show()].

f = show means assigning the address of the function show to the 'f' variable.

f=show is wrong.it should be replaced with show().then how the result came?

Show function has not been declared. Then how the error will not generate?